Here is the string:
format db "this is string a", 0, 0Ah
And I am trying to split it into this:
format
db
"this is string a"
0
0Ah
Is there any way can do this in python 2.7?
Thank you!
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is this a fixed string?Charlesliam– Charlesliam2014-01-29 04:04:16 +00:00Commented Jan 29, 2014 at 4:04
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@Charlesliam Hi, basically I am using Python to parse the assembly code, and I have to deal with stuff like this in parsing the data section of assembly code..lllllllllllll– lllllllllllll2014-01-29 04:05:39 +00:00Commented Jan 29, 2014 at 4:05
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1do you need those quotes to remain on the third string?roippi– roippi2014-01-29 04:08:04 +00:00Commented Jan 29, 2014 at 4:08
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@roippi No, not necessary.lllllllllllll– lllllllllllll2014-01-29 04:09:27 +00:00Commented Jan 29, 2014 at 4:09
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3 Answers
Use shlex.split:
s = 'format db "this is string a", 0, 0Ah'
import shlex
shlex.split(s)
Out[18]: ['format', 'db', 'this is string a,', '0,', '0Ah']
Your grammar is a little wonky with the trailing commas, but you can pretty safely rstrip that out:
[x.rstrip(',') for x in shlex.split(s)]
Out[20]: ['format', 'db', 'this is string a', '0', '0Ah']
3 Comments
Charlesliam
shlex.split is much better than re.split
jgritty
I agree, see how ugly my answer is.
lllllllllllll
groovy! Thank you roippi!
I'm sure there will be more elegant answers, but this'll work and preserve the quotes:
def parse(s):
s = s.split(', ')
stack = []
new = ''
inQuotes = False
for char in s[0]:
if char == '"':
inQuotes = True
if not inQuotes:
if not char == ' ':
new += char
else:
stack.append(new)
new = ''
else:
new += char
stack.append(new)
del s[0]
stack.extend(s)
return stack
>>> s = 'format db "this is string a", 0, 0Ah'
>>> parse(s)
['format', 'db', '"this is string a"', '0', '0Ah']
Comments
A regex solution:
import re
data = 'format db "this is string a", 0, 0Ah'
s = re.findall(r'''(?:[^ '"]+|'(?:[^']|\\.)*'|"(?:[^']|\\.)*")+''', data)
print [x.rstrip(',') for x in s]
output:
['format', 'db', '"this is string a"', '0', '0Ah']
1 Comment
Charlesliam
the output is one line?