how to find "http" in string from array?

Question

In PHP I have an array like this:

array
  0 => string 'open' (length=4)
  1 => string 'http://www.google.com' (length=21)
  2 => string 'blank' (length=5)

but it could also be like:

array
  0 => string 'blank' (length=5)
  1 => string 'open' (length=4)
  2 => string 'http://www.google.com' (length=21)

now it is easy to find "blank" with in_array("blank", $array) but how can I see if one string is starting with "http"?

I've tried with

array_search('http', $array); // not working
array_search('http://www.google.com', $array); // is working

now everything after `http? could vary (how to write vary, varie? could be different is what I mean!)

Now do I need a regex or how can I check if http exists in array string?

Thanks for advices

maybe this stackoverflow.com/questions/2354024/…

Millard
– Millard

2014-01-29 15:39:59 +00:00
Commented Jan 29, 2014 at 15:39 — Millard
– Millard, Commented Jan 29, 2014 at 15:39
How about a foreach loop with strpos?

Daryl Gill
– Daryl Gill

2014-01-29 15:45:22 +00:00
Commented Jan 29, 2014 at 15:45 — Daryl Gill
– Daryl Gill, Commented Jan 29, 2014 at 15:45
And there you go, preg_grep() to the rescue !

HamZa
– HamZa

2014-01-29 15:46:59 +00:00
Commented Jan 29, 2014 at 15:46 — HamZa
– HamZa, Commented Jan 29, 2014 at 15:46

ohaal · Accepted Answer · 2014-01-29 15:50:00Z

2

"Welcome to PHP, there's a function for that."

Try preg_grep

preg_grep("/^http\b/i",$array);

Regex explained:

/^http\b/i
 ^\  / ^ `- Case insensitive match
 | \/  `--- Boundary character
 |  `------ Literal match of http
 `--------- Start of string

edited Jan 29, 2014 at 15:50

answered Jan 29, 2014 at 15:44

ohaal

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Comments

Community · Accepted Answer · 2023-11-17 20:33:26Z

2

Try using the preg_grep function which returns an array of entries that match the pattern.

$array = array("open", "http://www.google.com", "blank");

$search = preg_grep('/http/', $array);

print_r($search);

edited Nov 17, 2023 at 20:33

CommunityBot

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answered Jan 29, 2014 at 15:44

sbeliv01

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Comments

hsz · Accepted Answer · 2014-01-29 15:45:40Z

2

Solution without regex:

$input  = array('open', 'http://www.google.com', 'blank');
$output = array_filter($input, function($item){
  return strpos($item, 'http') === 0;
});

Output:

array (size=1)
  1 => string 'http://www.google.com' (length=21)

answered Jan 29, 2014 at 15:45

hsz

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Comments

rccoros · Accepted Answer · 2014-01-29 15:47:36Z

0

You can use preg_grep

$match = preg_grep("/http/",$array);
if(!empty($match)) echo "http exist in the array of string.";

or you can use foreach and preg_match

foreach($array as $check) {
    if (preg_match("/http/", $check))
    echo "http exist in the array of string.";
}

answered Jan 29, 2014 at 15:47

rccoros

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1 Comment

HamZa Over a year ago

preg_match() in a loop is extremely slow, better use strpos() in this case

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