php syntax error if condition

Question

I want to include this if condition inside my code :

if(basename($_SERVER['REQUEST_URI']) == 'demo'){ // Do something }

I want to trigger a part of my code only when this condition is true, so my entire code is looking like this :

<?php

abstract class ECF_Field_Type {
    private static $types = array();
    protected $name;

    /* Constructor */
    public function __construct() {
        self::register_type( $this->name, $this );
    }

    /* Add a type to the types list */
    private static function register_type( $name, $type ) {
        self::$types[$name] = $type;
    }

    /* Return the appropriate type */
    public static function get_type( $name ) {
        return array_key_exists( $name, self::$types )
            ? self::$types[$name] : self::get_default_type();
    }

    /* Return all types */
    public static function get_types() {
        return self::$types;
    }

    /* Get default type */
    public static function get_default_type() {
        return self::get_type( 'text' );
    }

    /* Display form field */
    public abstract function form_field( $name, $field );

    if(basename($_SERVER['REQUEST_URI'])) == 'demo'){

        public function display_field( $id, $name, $value ) {
            return "<span class='ecf-field ecf-field-$id'>"
                . "<strong class='ecf-question'>$name:</strong>"
                . " <span class='ecf-answer'>$value</span></span>\n";
        }

    }

    /* Display field plain text suitable for email display */
    public function display_plaintext_field( $name, $value ) {
        return "$name: $value";
    }

    /* Get the description */
    abstract public function get_description();
}
?>

When I'm checking this in my browser I get Parse error: syntax error, unexpected T_IF, expecting T_FUNCTION in if(basename($_SERVER['REQUEST_URI']) == 'demo'){

If I put this if(basename($_SERVER['REQUEST_URI']) == 'demo'){ // Do something } outside the abstract class ECF_Field_Type { the condition is working fine.

How can I get that ifcondition to work inside that abstract class ?

I just want to be able to run that public function display_field( $id, $name, $value ) when that condition is true.

You should allways avoid dynamic code in your application. no matter if it's a function or a class. It will result into loads of problems! — ToBe
– ToBe, Commented Jan 30, 2014 at 15:19

Marc B · Accepted Answer · 2014-01-30 15:17:56Z

5

You cannot have code "outside" of a method in a class. e.g.

class foo {
   if (true) { ... };   <---bad code
   function bar() {
      if (true) { ... } <-- ok code
   }
}

answered Jan 30, 2014 at 15:17

Marc B

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Comments

Volkan Ulukut · Accepted Answer · 2014-01-30 15:19:36Z

1

try this:

public function display_field( $id, $name, $value ) {
if(basename($_SERVER['REQUEST_URI']) == 'demo'){
    return "<span class='ecf-field ecf-field-$id'>"
        . "<strong class='ecf-question'>$name:</strong>"
        . " <span class='ecf-answer'>$value</span></span>\n";
  }
else 
return "";
}

answered Jan 30, 2014 at 15:19

Volkan Ulukut

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