PHP Array Looping & Exploding

Question

I'm not very experienced in using PHP, but I'm having a hard time thinking of a way to do this. I'm reading from a file and exploding on ":" as you can see here.

<?php
$datainfo = file('data.txt');
for($i = 0; $i < count($datainfo); $i++){
$expdata = explode(':', $datainfo[$i]);
}

?>

The issue is that I need to reference specific indexes of the resulted explosion like this.

<p> <?php echo $expdata[1] ?> </p>

I'm getting back an array of the last line inside the data.txt file. I know why It's happening, I just don't know how to get what I want here. (Sorry Very New). Data.txt contain the following.

name:Octopod Juice Stand
balance:20
price:0.5
customers:12
starting:2014-05-26
end: 2014-09-01
juice:15.25
fruit:10

Do $expdata[] instead of $expdata. You are reassigning the variable with each loop thats why you get the last line only. — Rahil Wazir
– Rahil Wazir, Commented Feb 2, 2014 at 15:58
When I did that, it just echos out the word "Array" so I'm assuming it 's empty for some reason. — Corjava
– Corjava, Commented Feb 2, 2014 at 16:00
Do print_r($expdata) instead of echoing and see the array dump. — Rahil Wazir
– Rahil Wazir, Commented Feb 2, 2014 at 16:02
Because $expdata will be a two-dimensional array, so $expdata[1] will refer to array('balance', '20') — Mark
– Mark, Commented Feb 2, 2014 at 16:02

Nathan Dawson · Accepted Answer · 2014-02-02 16:06:04Z

1

Change your code to

<?php
$datainfo = file('data.txt');
$expdata = array();

for($i = 0; $i < count($datainfo); $i++){
    $expdata[] = explode(':', $datainfo[$i]);
}

?>

And then to get the first label.

<p><?php echo $expdata[0][0]; ?></p>

Or the first value

<p><?php echo $expdata[0][1]; ?></p>

answered Feb 2, 2014 at 16:06

Nathan Dawson

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1 Comment

Corjava Over a year ago

Yeah, thank you for this, I noticed this reading one of the comments. I'm pretty tired and didn't even think about it being two dimensional.

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