How to put my php variable inside of startDate:'01-01-1996 ?
I want just like this startDate:'01-01-date' How to do that?
$curYear = date('Y');
<script type = "text/javascript"charset = "utf-8">
$(function () {
var date = "<?php echo $curYear; ?>";
$('.date-pick').datePicker({
startDate: '01-01-1996'
});
});
</script>
Try
var date = <?php echo $curYear; ?>;
$('.date-pick').datePicker({startDate:date });
var date = '01-01-' + <?php echo $curYear; ?>;
$('.date-pick').datePicker({startDate:date });
$date = '01-01-'.date('Y'); //in php
var date = <?php echo $date; ?>;
$('.date-pick').datePicker({startDate:date });
What about this?:
<script type = "text/javascript"charset = "utf-8">
$(function () {
var date = "<?php echo $curYear; ?>";
$('.date-pick').datePicker({
startDate: '01-01-<?=date("Y")?>'
});
});
</script>
It's really a very bad idea to mix jQuery with PHP. Try to find another way.
If you need current year:
$(function () {
var cur_year = new Date().getFullYear();
$('.date-pick').datePicker({
startDate: '01-01-'+cur_year
});
});
If only php script can do it (e.g. if this value is stored in DB) you can use ajax
$(function () {
$.get('path_to_script_that_returns_year.php', function(resp) {
$('.date-pick').datePicker({
startDate: '01-01-'+resp
});
});
});
where php script could be
<?php
// ...
// get your year and send
// ...
echo $var_with_year;
if you want to echo variable in javascript or jquery then you want to simply using one line code
<?php echo $variable_name;?>;
