char c;
int i;
for(i=0;i<5;i++)
{
printf("Enter a character : ");`
scanf("%c",&c);
}
getch();
The above code doesn't work properly.It is getting input for only 3 times. I am not able to find solution for it.Please help with it.Thanks in advance !!
This is because of the new-line character \n left behind by the previous scanf is read by the scanf in the next iteration. Place a space before the %c specifier to consume the \n
scanf(" %c",&c);
^Notice the space
char c is a single character variable.
In your code, your are reading time and time again characters and storing it into c, effectively overwriting it each time. If you would like to input multiple characters, consider using a character array likewise:
#include <stdio.h>
int
main (void)
{
char c[5];
int counter;
for (counter = 0; counter < 5; counter++)
{
printf ("Enter a character: ");
scanf ("%c\n", &c[i]);
}
printf ("The string you input is %s\n", c);
return 0;
}
Suppose you enter a, b and c on the screen then it is actually taking 5 inputs
Input 1: a
Input 2: \n
Input 3: b
Input 4: \n
Input 5: \n
The newline is also taken as input
aand hits return the code will readaand then read\n.