Passing a char pointer array to a function in c++

Question

I am trying to make a tic tac toe game and I want to pass my 2d array of the tic tac toe board positions to my function that draws the updated board. I want the parameter value of my function "updateBoard" to be able to take in the memory adress of the board from main so I can use it all throughout my program without worrying about scope. I am getting an error as so when i compile it:

error C2664: 'updateBoard' : cannot convert parameter 1 from 'char (*)[3][3]' to 'char *[][3]' 1> Types pointed to are unrelated; conversion requires reinterpret_cast, C-style cast or function-style cast

heres my code:

#include "stdafx.h"
#include <iostream>

using namespace std;

void updateBoard (char *n[3][3])
{

}
int getMove ()
{
int input;
cout <<"\n";
cout <<"1 for square 1| 2 for square 2| and so on...  : ";
cin >>input;

return 0;
}

int main ()
{
const int WIDTH = 3;
const int HEIGHT = 3;
char board [WIDTH][HEIGHT] = {' ', ' ', ' ',
                              ' ', ' ', ' ',
                              ' ', ' ', ' '};
updateBoard(&board);
char f;
cin >>f;
}

Vlad from Moscow · Accepted Answer · 2014-02-05 04:33:10Z

1

You can do the following way

#include "stdafx.h"
#include <iostream>

using namespace std;

const int WIDTH = 3;
const int HEIGHT = 3;

typedef char TBoard [WIDTH][HEIGHT];

void updateBoard ( TBoard board, int width )
{

}

int main ()
{
TBoard board = {' ', ' ', ' ',
                ' ', ' ', ' ',
                ' ', ' ', ' '};
updateBoard( board, WIDTH);
char f;
cin >>f;
}

As for your error then the function parameter shall be defined as

void updateBoard (char ( *n )[3][3])
{

}

char ( *n )[3][3] means pointer to a two-dimensional array while

char * n[3][3] means a two dimensional array of pointers char *

And inside the function you should to write

( *n )[i][j]

to access the element with indexes i and j.

edited Feb 5, 2014 at 4:33

answered Feb 5, 2014 at 3:53

Vlad from Moscow

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