How to parse json data from php to jQuery

Question

I have a curl statement that pulls json formatted array to php. I then want to transfer this array to jQuery so that the client side will hold the array. I'm currently using the below method:

<script>var obj = jQuery.parseJSON( <?php echo var_dump($json_short); ?> );</script>

The client sees something like:

<script>var obj = jQuery.parseJSON( array(1) {
  ["search"]=>
  array(50) {
    [0]=>
    array(6) {
      ["id"]=>
      string(6) "641279"
      ["description"]=>
      string(36) "Instyle - Responsive Portfolio Theme"
      ["url"]=>
      string(69) "http://themeforest.net/item/instyle-responsive-portfolio-theme/641279"
      ["type"]=>
      string(9) "wordpress"
      ["sales"]=>
      string(3) "135"
      ["rating"]=>
      string(3) "4.5"
    }
    ....
  }
}
 );</script>

Will obj now hold the array? is this the right way becuase I'm getting an error:

Uncaught SyntaxError: Unexpected token {

Although your question is a lil confusing, i believe you should use print_r instead of var_dump — clouddreams
– clouddreams, Commented Feb 6, 2014 at 15:14

Community · Accepted Answer · 2023-11-17 20:33:26Z

2

PHP has json_encode function already, you should use that.

Would look like:

<script>
var a = <?php echo json_encode($json_short); ?>;

</script>

edited Nov 17, 2023 at 20:33

CommunityBot

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answered Feb 6, 2014 at 15:11

Jage

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2 Comments

Pitchinnate Over a year ago

You would need quotes around this for it to store as a string.

Jage Over a year ago

That is true, but he does not want to have a string. He wants a native object or array, hence the proposed use of parseJSON() in order to convert from string to usable object.

Emilio Rodriguez · Accepted Answer · 2014-02-06 15:11:21Z

1

You cannot use a direct dump, you need to json_encode first:

<script>var obj = <?php echo json_encode($json_short) ?>;</script>

answered Feb 6, 2014 at 15:11

Emilio Rodriguez

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Comments

jona303 · Accepted Answer · 2014-02-06 15:13:31Z

0

I don't understand what you're trying with <script>var obj = jQuery.parseJSON( <?php echo var_dump($json_short); ?> );</script>

in PHP try echo json_encode($json_short);

answered Feb 6, 2014 at 15:13

jona303

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Comments

Sam Pettersson · Accepted Answer · 2014-02-06 15:17:22Z

0

the var_dump function doesn't dump it as a json object.

use json_encode instead of var_dump.

answered Feb 6, 2014 at 15:17

Sam Pettersson

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Comments

Pitchinnate · Accepted Answer · 2014-02-06 15:11:46Z

-1

Don't use var_dump first off. Next make sure you have converted your variable to a json array you have a normal array.

<script>var obj = jQuery.parseJSON( <?php echo json_encode($json_short); ?> );</script>

answered Feb 6, 2014 at 15:11

Pitchinnate

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4 Comments

Jage Over a year ago

he shouldn't even need to use parseJSON. That takes a string and turns it into an array or obj or whatever. If json_encode is used, the data is immediately usable in javascript.

Pitchinnate Over a year ago

Only if he wants to use it as a string if he actually wants to be able to access the data like obj.search[0].id then he would need to parse it.

Pitchinnate Over a year ago

Also if he just wants to store it as a string then ' or " would need to go around it.

Jage Over a year ago

He would have to parseJSON if he has a string. Using json_encode allows him to skip that step since it will be placed in javascript as a usable object.

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