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First off, I know that this sort of a duplicate, but I believe that my problem is different from the other question on the same topic (read: more n00by).

Basically, I'm trying to use this script. To make my code neater and more easily human-readable, I decided to put it into a seperate script, wrap the whole thing in a function with a path parameter, and then call the function (after setting up the script on the main page) with a the path to the image I wanted to use.

My question is pretty basic; what's the correct way to format the path? Do I format the path when I pass it to the function as a string? Right now, what I have isn't working.

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The path will be always a string but the path format depends.

You can use either relative or absolute path.

I'd recommend you to try the relative path first. For example, if your image is in a parent folder from your page, use var cursorpath="../cursor.gif";.

For absolute paths you need to provide the full path and match the same protocol used for your page. For example, if your image is in C:/dev/images/cursor.gif and you're running your page directly from the file, you should use var cursorpath="file:///C:/dev/images/cursor.gif".

Let me know if this solve your problem.

EDIT

If the image is in a folder at the same level of your page use:

cursorpath="img/cursor.gif"; //Without the '/' in the beginning

For example, if we are at the page http://google.com/search/index.html and add two <img> like this:

<img src="images/sample.png">
<img src="/images/sample.png">

The first one will search for an image at http://google.com/search/images/sample.png.

The second one will try this path beggining from the website root (the /), like this http://google.com/images/sample.png.

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So I'm trying to use an image in a folder called img. The folder is in the same directory as the index.html file that I'm calling the function from. In this case, would I use var cursorpath="/img/cursor.gif";?
And, if I'm passing this directory to a function instead of as a variable, would I keep the quotes?
@evamvid Yes keep the quotes, they can be either double or simple.
So I would apply this the same way when passing an argument to the function? The original script uses cursorpath as a variable. My objective is to wrap it in a function called cursor, with path as an argument. cursorpath would be set equal to path.
If you declared the function like this: function cursor(cursorpath){ ... } you already have the cursorpath variable inside that function. So you can call like this: cursor("img/cursor.gif");. Got it?
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