extract a float from a string in javascript

Question

I know that we can extract an integer value from a string using

var x = "> 1";
x = parseInt(x.match(/\d+/)[0], 10));

How do I get a float value from a string

example: var x = "> 1.1"

I know we can just use x.substring(2);

But for a more generic solution? since the above will not give the accurate result for

var x = "1.1"

So what is the best way to extract the float value 1.1 from

var x = "> 1.1"

How about /\d+\.?\d*/

Matt Burland
– Matt Burland

2014-02-07 18:18:02 +00:00
Commented Feb 7, 2014 at 18:18 — Matt Burland
– Matt Burland, Commented Feb 7, 2014 at 18:18

Barmar · Accepted Answer · 2014-02-07 18:19:43Z

5

Use parseFloat and a regular expression that matches a number with optional decimals and minus sign.

var f = parseFloat(x.match(/-?(?:\d+(?:\.\d*)?|\.\d+)/)[0]);

answered Feb 7, 2014 at 18:19

Barmar

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Comments

Bablu Ahmed · Accepted Answer · 2020-06-29 15:26:30Z

2

You can try the following one to extract only numbers like floating or integer as an array as many as you want using the match function.

str = 'On schedule: 3243.8 miles away (4491 minutes)';
values = str.match(/[0-9.]+/g); //=> ["3243.8", "4491"]

answered Jun 29, 2020 at 15:26

Bablu Ahmed

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Comments

Stephen O'Connor · Accepted Answer · 2014-02-07 18:22:43Z

1

x = parseFloat(x.match(/[-+]?([0-9]*\.[0-9]+|[0-9]+)/));

answered Feb 7, 2014 at 18:22

Stephen O'Connor

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2 Comments

War10ck Over a year ago

Please explain your solution so that future visitors to this question will understand how it solves the problem at hand.

Stephen O'Connor Over a year ago

The argument matches a number with an optional + or - sign followed by at least one digit followed by an optional decimal point with at least one digit following the decimal point.

canon · Accepted Answer · 2014-02-07 18:21:21Z

0

Use parseFloat(). It does exactly what you're looking for.

edited Feb 7, 2014 at 18:21

canon

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answered Feb 7, 2014 at 18:19

user1710796

1 Comment

Barmar Over a year ago

It won't skip over the > at the beginning.

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