Been lurking on Stackoverflow for a long time but this is my first post. I am receiving a error related to displaying an array which is supposed to be populated by a mysql query. The echo function just returns ArrayArrayArray instead of what is supposed to be there. The mysql query is comparing a form input (the variable $data) .
<?php
$data = $_POST["search"];
global $data;
// Create Connection
$con = mysqli_connect(xxxxx,xxxxxx,xxxxx,xxxxx);
// Check Connection
if (mysqli_errno($con))
{
echo "Failed To Connect To The Database" ;
}
//Perform Query To Compare And Return Results
$result_array = array();
$query = " SELECT url FROM data WHERE url LIKE '%$data%' " ;
$result = mysqli_query($con, $query);
// While Loop To Return All Comparable Results
while ($row = mysqli_fetch_array($result)) {
$result_array[] = $row['url'];
echo $result_array ;
}
?>
print_r($result_array)orvar_dump($result_array)echocommand. You should use something else (as suggested in the other comments) to print the contents of an array.mysqliyou should be using parameterized queries andbind_paramto add user data to your query. DO NOT use string interpolation to accomplish this because you will probably create severe SQL injection bugs.