How to put a string variable in JSONObject

Question

I have a JSONObject:

JSONObject data = new JSONObject("{\"alert\": \"The Mets scored!\", \"action\": \"com.vipulk.acuv.UPDATE_STATUS\",\"ph\": ph }");

I have a string defined as:

     String ph="this is String";

Now when i receive this JSONObject on receiver side I have the value of "ph" as "ph". I want the value of original String ph. How to do it. Can JSONObject send extra strings with another method.

Pardon my limited knowledge about JSON, as I am using it just once so I am avoiding going deep. I have everything done except putting this string variable in JSONObject.

NOTE: I am working with PARSE push notifications and I've to send this object in a push notification (that i am able to do).

What do you mean by I have the value of "ph" as "ph" ?

Paresh Mayani
– Paresh Mayani

2014-02-11 09:03:09 +00:00
Commented Feb 11, 2014 at 9:03 — Paresh Mayani
– Paresh Mayani, Commented Feb 11, 2014 at 9:03

nikis · Accepted Answer · 2014-02-11 07:39:12Z

4

If you want to modify your JSONObject, you can use .put method (http://json.org/javadoc/org/json/JSONObject.html#put%28java.lang.String,%20java.lang.Object%29):

data.put("ph", ph);

answered Feb 11, 2014 at 7:39

nikis

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3 Comments

VipulKumar Over a year ago

Thanks. That worked. I wasn't sure about using .put method. As there wasn't any mention of putting a string value in the docs (none that I could find)

Manjunath Hegde Over a year ago

Why that didn't work for me? JSONObject Customer= new JSONObject(); Customer.put("name",name);

Robert Lewis Over a year ago

Is it just an error in the Android documentation that there is no mention of putting a String into a JSON object? developer.android.com/reference/org/json/JSONObject

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