I have the following Json String:
var jsonString = '{"Users":[{"Name":"abc","Value":"test"},{"Name":"def","Value":"test"}]}';
I am trying to use ZF2's JsonModel class (Zend\View\Model\JsonModel) in the controller to render my view with the above JSON string. However, it seems to take only an array instead of a JSON String.
How do I make the controller return a JSON string?
Thanks
You don't need to use a JsonModel since your json is already "rendered", so, you can set it directly in response object and return it:
/**
* @return \Zend\Http\Response
*/
public function indexAction()
{
$json = '{"Users":[{"Name":"abc","Value":"test"},{"Name":"def","Value":"test"}]}';
$this->response->setContent($json);
return $this->response;
}
That will short-circuit the dispatch event, so the application will return your response immediately, without calling the view layer to render it.
See http://framework.zend.com/manual/2.2/en/modules/zend.mvc.examples.html#returning-early
You have to use the acceptableViewModelSelector controller plugin
public function listAction()
{
$acceptCriteria = array(
'Zend\View\Model\ViewModel' => array(
'text/html',
),
'Zend\View\Model\JsonModel' => array(
'application/json',
));
$viewModel = $this->acceptableViewModelSelector($acceptCriteria);
Json::$useBuiltinEncoderDecoder = true;
$itemsList = $this->getMyListOfItems();
return $viewModel->setVariables(array("items" => $itemsList));
}
The official doc : http://framework.zend.com/manual/2.2/en/modules/zend.mvc.plugins.html#zend-mvc-controller-plugins-acceptableviewmodelselector
Another bonus : explanation of why using this plugin
Add in module.config.php:
'strategies' => [
'ViewJsonStrategy',
],
Then you can return in controller json response:
return new JsonModel(['some'=>'data']);
