Is it possible to obtain a variable from a parent function without declaring that function in parenthesis when calling the function (not possible in this instance).
function list_posts($filter_by_date){
/* Dome things to do first 8*/
function filter(){
/* Do something that involves the variable $filter_by_date */
}
}
You can use closures:
function list_posts($filter_by_date){
/* Dome things to do first 8*/
$filter = function() use($filter_by_date) {
echo $filter_by_date; // outputs "test"
/* Do something that involves the variable $filter_by_date */
};
$filter();
}
list_posts("test");
Yes, declare them separately and use arguments:
function filter($arg){
echo 'filter() got: ', $arg, PHP_EOL;
}
function list_posts($filter_by_date){
echo 'list_posts() got: ', $filter_by_date, PHP_EOL;
filter($filter_by_date);
}
list_posts(date('d.m.Y'));
Yes, this is possible if you use a anonymous function:
function list_posts($filter_by_date) {
// Dome things to do first 8*/
$filter = function () use($filter_by_date) {
// Do something that involves the variable $filter_by_date
};
// Call the filter function
$filter();
}
You can use global.
function list_posts($filter_by_date){
global $filter_by_date;
// do something with variable
}
function filter(){
global $filter_by_date;
echo $filter_by_date;
}
