I just want ask, is it possible to initiliaze more objects with same constructor in one command?
Example of code:
Tile[] tiles = new Tile(5,5)[20];
Thanks for response.
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4No, it is not possible. Use a for loop.Sotirios Delimanolis– Sotirios Delimanolis2014-02-17 03:25:51 +00:00Commented Feb 17, 2014 at 3:25
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3 Answers
Impossible as far as I know.
The code Tile[] tiles = new Tile[20]; just creates an array of references. To fill the array, you should create a Tile object and then assign the reference to one index of the array, such as:
tiles[0] = new Tile(5,5);
If all elements of the array pointing to the same object is OK, you can full fill the array simply use:
Tile tiles = new Tile[20];
Arrays.fill(tiles, new Tile(5,5));
4 Comments
Sotirios Delimanolis
Pretty much the shortest you can do with JDK libs.
Radiodef
@user2899587 Do note that
Arrays.fill fills the array with a single object.
user2573153
out of curiosity, would this fill the entire array with a deep or shallow copy of that object?
Weibo Li
@user2573153: Only a shallow copy.
No, you have to use a loop.
Tile[] tiles = new Tile[20];
for(int i = 0; i < tiles.length; i++) {
tiles[i] = new Tile(5, 5);
}
However, it is nice that in Java 8 we will be able to shorten this using the new Supplier class and a helper method.
static <E> E[] fill(E[] arr, Supplier<? extends E> supp) {
for(int i = 0; i < arr.length; i++) {
arr[i] = supp.get();
}
return arr;
}
We can then do the following:
Tile[] tiles = fill(new Tile[20], () -> new Tile(5, 5));
I think that's sort of nifty.
There's also a couple ways to do this without Java 8 by using reflection. Here's a way you can do it if the class has a copy constructor (a constructor that takes an object of its own class as an argument):
static <E> E[] duplicate(E[] arr, E element) {
@SuppressWarnings("unchecked")
Class<? extends E> cls = (Class<? extends E>)element.getClass();
try {
Constructor<? extends E> ctor = cls.getConstructor(cls);
for(int i = 0; i < arr.length; i++) {
arr[i] = ctor.newInstance(element);
}
} catch(Exception e) {
e.printStackTrace(System.err);
}
return arr;
}
So for example:
String[] arr = fill(new String[5], "Hello world!");
Reflection is a bit more unstable than the lambda, especially when dealing with subtypes and primitives. The lambda is great.
2 Comments
Adrian Shum
oops... was thinking of the exact solution but I was slow in posting :P
Radiodef
Here it is on TryJava8.com.
First, it is even not possible to initialize an object array with non-null value in one line (ok, except using {...} or filling them with same reference but I think it is not what you want)
You gotta create instance of array first, and fill individual element in the array:
e.g.
Foo[] myArray =new Foo[10];
for (int i = 0; i < myArray.length; ++i) {
myArray = new Foo();
}
If you are just looking for shorter code that you don't want to write the loop again and again, here is one option for you:
write a little util like this:
public class ArrayUtil {
public static T[] fillArray(T[] array, ArrayElementFactory elementFactory) {
for (int i = 0; i< array.length; ++i) {
array[i] = elementFactory.create(i);
}
return array;
}
}
public interface ArrayElementFactory<T> {
T create(int i);
}
The way to use is something like
Foo[] fooArray = fillArray(new Foo[10], new ArrayElementFactory<Foo>() {
Foo create(int i) { return new Foo(10,10); }};
If you are using Java8, I believe (haven't tried) you can use lambda expression which give you something like
Foo[] fooArray = fillArray(new Foo[10], i -> new Foo(10,10));
