How implement 'include' into printf?

Question

I use in project such functions:

include ("blocks/myCompanyCommentsListBlock.php");

I need somethig like this:

$str = sprintf("<div>%s</div>", include ("blocks/myCompanyCommentsListBlock.php"));

How this can be done? :) Any links would be useful :)

do you want the full contents of "myCompanyCommentsListBlock.php" [file_get_contents()] ? or is it php code to run ? — user557846
– user557846, Commented Feb 17, 2014 at 21:26
Use functions. Put the code of the include file in a function, include it before the assignment and call the function in the assignment. — jeroen
– jeroen, Commented Feb 17, 2014 at 21:27
Can this not be done by echo '<div>'; include 'inc.php'; echo '</div>'; ? — humbolight
– humbolight, Commented Feb 17, 2014 at 21:28

zerkms · Accepted Answer · 2014-02-17 21:31:01Z

4

Use output buffering to prevent its content from being sent to the browser. Then use ob_get_clean() to capture its output into a variable.

ob_start();
include ("blocks/myCompanyCommentsListBlock.php");
$content = ob_get_clean();
$str = sprintf("<div>%s</div>", $content);

zerkms

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answered Feb 17, 2014 at 21:28

John Conde

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2 Comments

@zerkms That's what I was looking for. I had done this once years ago and forgot exactly what it was I did.

Useful to write note to remember this :)