Linux Shell Script Input

Question

I'm trying to tell a shell script information this way (when I execute it via SSH):

bash myscript.sh 'input1' 'input2' 'input3'

However I've no idea on how to convert the inputs 1, 2 and 3 into variables in shell script, like $var1, $var2 and $var3.

Anybody know how?

Prix · Accepted Answer · 2014-02-18 09:11:01Z

3

Its very simple, the arguments passed are held in their respective numbers:

input1 would be on $1
input2 would be on $2
input3 would be on $3

And if I recall it correctly $0 is the script path/filename

And you can for example do this:

#!/bin/sh

echo "arg1='$1' - arg2='$2' - arg3='$3'"
var1="$1"
var2="$2"
var3="$3"
echo "var1='$var1' - var2='$var2' - var3='$var3'"

Not really needed but just to illustrate.

answered Feb 18, 2014 at 9:11

Prix

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5 Comments

Does it need to be like $var1="$1" $var2="$2" $var3="$3"?

@user2248259 you can directly use $1 instead of assigning it to a variable.

I know, but I need to convert $1 to $var1

@user2248259 then you have to use var1="$1" just like I did on the example above.

Shell is not Perl; the dollar sign is only needed to expand the variable to its value, not to assign to it.