Laravel 4 - ErrorException Undefined variable

Question

Trying to bind model to the form to call update function, but model is not found.

{{ Form::model($upload, array('url' => array('uploads/update', $upload->id), 'files' => true, 'method' => 'PATCH')) }}

Controller to get edit view

public function getEdit($id)
{
 $upload = $this->upload->find($id);

if (is_null($upload))
{
  return Redirect::to('uploads/alluploads');
}

 $this->layout->content = View::make('uploads.edit', compact('uploads'));
}

Controller to do the update

public function patchUpdate($id)
{
  $input = array_except(Input::all(), '_method');

  $v = Validator::make($input, Upload::$rules);

  if ($v->passes())
  {
    $upload = $this->upload->find($id);
    $upload->update($input);

    return Redirect::to('uploads/show', $id);
  }

  return Redirect::to('uploads/edit', $id)
   ->withInput()
   ->withErrors($v)
}

error i get

ErrorException
Undefined variable: upload (View: /www/authtest/app/views/uploads/edit.blade.php)

In routes I have Route::controller('uploads', 'UploadsController'); — cch
– cch, Commented Feb 18, 2014 at 23:53
Then you have to pass the model from the controller when loading/showing the form, how do you show the form, code ? — The Alpha
– The Alpha, Commented Feb 18, 2014 at 23:54
I updated my question above, I get the selected id and pass that to the edit view — cch
– cch, Commented Feb 19, 2014 at 0:01
Its PHP error processed by Laravel error handler. Its nothing related to Laravel actually. Answer below is good one. — Rolice
– Rolice, Commented Feb 19, 2014 at 0:06

The Alpha · Accepted Answer · 2014-02-19 00:12:52Z

1

If you are not binding the model in the route then pass it from the controller when showing/loading the form for editing, for example:

public function getEdit($id)
{
    $upload = $this->upload->find($id);
    if (is_null($upload))
    {
        return Redirect::to('uploads/alluploads');
    }
    $this->layout->content = View::make('uploads.edit', compact('upload')); //<--
}

Update: You should use compact('upload') not uploads because the variable is $upload.

edited Feb 19, 2014 at 0:12

answered Feb 19, 2014 at 0:02

The Alpha

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4 Comments

The Alpha Over a year ago

It's probably because of if condition, probably $this->upload->find($id) returns null.

cch Over a year ago

In the url I can see that the correct id is passed. Does that mean the is not returning null ?

The Alpha Over a year ago

Yes, it's not null then, remove the if condition and check if works.

cch Over a year ago

I removed the if condition as well, something else has to create this empty page, I can't seem to find it right now. Thanks for you help anyway.

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