How do I pass a regex parameter to a preg replace callback in PHP?

Question

I am using preg_replace_callback to parse my [quote id=123][/quote] bulletin board code tag. What is the correct way to pass the quote id with a regex parameter?

$str = '[quote id=123]This is a quote tag[/quote]';

$str = preg_replace_callback("^[quote id=([0-9]+)](.*?)[/quote]^", _parse_quote("123", "message"), $str);

function _parse_quote($message_id, $original_message){

    $str = '<blockquote>'.$original_message.'</blockquote>';

    return $str;

}

falsetru · Accepted Answer · 2014-02-19 06:40:50Z

2

The regular expression should be fixed.

[ and ] should be escaped to match them literally. ([, ] have special meaning in regular expression).

The code is calling _parse_quote instead of passing the function to the preg_replace_callback. Just pass the function name as string.

You can access the captured group by indexing. ($matches[2] to get the second captured group)

$str = '[quote id=123]This is a quote tag[/quote]';
$str = preg_replace_callback("^\[quote id=([0-9]+)\](.*?)\[/quote\]^", "_parse_quote",  $str);
echo $str;

function _parse_quote($matches) {
    $str = '<blockquote>' . $matches[2] . '</blockquote>';
    return $str;
}

output:

<blockquote>This is a quote tag</blockquote>

edited Feb 19, 2014 at 6:40

answered Feb 19, 2014 at 6:35

falsetru

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