read files with loop in MATLAB

Question

I am reading all files from a directory. But then I want to loop over it and load the files with the number of iterator of the loop, like this

A = dir('*.txt');
for i=1:size(A)
   text = function('Text'+i+'.txt');
end

So my problem is, I can't find the right syntax to get the text file at the i-position. Thanks!

sebastian · Accepted Answer · 2014-02-20 10:31:39Z

5

You can't simply add strings like 'Text' and numbers i. You'll have to convert i to a string first and then concatenate the three:

text = function(['Text', num2str(i), '.txt']);

Alternatively, my preferred solution would be to use sprintf:

text = function(sprintf('Text%i.txt', i));

sprintf will replace the %i part in the string by the integer-representation of i.

EDIT:

Re-reading your question, you might be better off using the information from dir instead of building your own filenames:

text = function(A(i).name);

The structure A will contain information on every file - including its name. This would make your code somewhat more stable.

edited Feb 20, 2014 at 10:31

answered Feb 20, 2014 at 9:55

sebastian

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2 Comments

Baloo Over a year ago

Thank you! My problem is, there are more *.txt files in the directory than I want use. Is it possible to say something like "add every file to A which starts with the letter 't' and has the extension '.txt'?

sebastian Over a year ago

Well, you can obviously do A = dir('t*.txt').

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