JavaScript recursive replace in Object

Question

Folks, I have the following JSON object, in which I would like to recursively find every occurrence of foo with bar.

Also the [Object] can potentially contain foo which would also need to be replaced.

{ _id: 530797d8952e10129f97fde3,
  Product: 'something',
  Realm: [ 'something', 'something','foo' ],
  Service: 'Node',
  Owners: [ 'foo', 'something' ],
  Project: 'something',
  URLs:
    [ { 'foo': [Object] },
      { 'foo': [Object] },
      { 'foo': [Object] } ] }

How would i loop through this? I've tried with but failed:

var cleanObject = {}
for (key in dirtyObject) {
    key = key.replace('foo', 'bar');
    cleanObject[key] = dirtyObject[key];
}

Your title mentions recursion (which seems reasonable) but the code you show doesn't include any. Are you asking how to do recursion? Or is there more code that you haven't shown. — Stephen Thomas
– Stephen Thomas, Commented Feb 21, 2014 at 18:34

Niet the Dark Absol · Accepted Answer · 2014-02-21 18:34:35Z

3

Tip: That's not a "JSON object". There is no such thing as a "JSON object". "JSON" is a string, representing an object. What you have there is an object literal.

However, JSON can help. Consider trying:

var cleanObject = JSON.parse(JSON.stringify(dirtyObject).replace(/foo/g,'bar'));

answered Feb 21, 2014 at 18:34

Niet the Dark Absol

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7 Comments

Stephen Thomas Over a year ago

That will replace in both keys and values. If I'm reading the question correctly, the OP only wants to replace keys.

Niet the Dark Absol Over a year ago

@StephenThomas True. But I'm reading the question as "every occurrence", and the code as a botched attempt to do so that only replaces keys. The question is ambiguous as to that point...

Stephen Thomas Over a year ago

gotta agree. not sure what the OP really wants here

Cmag Over a year ago

Essentially I want EVERY occurrence to be replaced, thanks guys

Cmag Over a year ago

And your result worked. Wish I could award more points to your solution. This solves a ton of work for me. Thanks

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