PHP variable scope in a static method

Question

I'm having trouble getting access to a variable that is available outside of my method call. (Using Laravel) An example:

    print "Here is my name: $name\n";

    return Foo::find(1)->whereHas('bar', function($q) {
        global $name;
        print "Unfortunately this name is blank: " . $name;
        $q->where('name', 'like', '%' . $name . '%');
    })->first();

$name inside the whereHas function is always blank. If I don't declare it as $global, then I get a warning that $name doesn't exist at all. How do I get access to it?

traq · Accepted Answer · 2014-02-21 23:32:01Z

2

You can send references to anonymous functions (i.e., Closures) with the use keyword:

$name = 'foo';
return Foo::find(1)->whereHas('bar', function($q) use ($name) {
    print "Here name should be : " . $name; // foo
    $q->where('name', 'like', '%' . $name . '%');
})->first();

btw i have not tested this, but its supposed to work

edited Feb 21, 2014 at 23:32

traq

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answered Feb 21, 2014 at 23:02

markcial

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1 Comment

Anthony Over a year ago

Nice shot sir! I had no idea about the use() keyword. Worked like a charm. Thanks!

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