XPath Query using contains with multiple values

Question

I need an XPath that will elect all parent nodes a child with anattribute that constains at least one of a list of values.

Example XML

<mynodes>
  <theParentNode>
    <theChildNode name="one two" />
  </theParentNode>
    <theParentNode>
    <theChildNode name="one all" />
  </theParentNode>
    <theParentNode>
    <theChildNode name="two" />
  </theParentNode>
    <theParentNode>
    <theChildNode name="all" />
  </theParentNode>
</mynodes>

I want to select all nodes where name contains "one" OR "all" (or any other combination for that matter). So that the returned nodeList is:

<theParentNode>
  <theChildNode name="one two" />
</theParentNode>
<theParentNode>
  <theChildNode name="one all" />
</theParentNode>
<theParentNode>
  <theChildNode name="all" />
</theParentNode>

So far my query looks like this (note im not using a schema):

//theChildNode[contains(tokenize(@name, '\s'), "one")]

Which will get me all the vendor elements containing "one" in their name attribute. But im unsure how to go about supplying multiple values in place of the "one", and then the best way to step back up to theParentNode. I could always just do all of this in php but id rather just do it with a XPath if possible.

Why are you using "tokenize"? The "contains" function only operates on strings and will internally concatenate the tokenized string. — chiborg
– chiborg, Commented Jun 25, 2010 at 10:03

sp00m · Accepted Answer · 2013-10-25 09:42:26Z

5

A bit redundant, but this should do it:

//theChildNode[contains(tokenize(@name, '\s'), "one") or contains(tokenize(@name, '\s'), "all")]

edited Oct 25, 2013 at 9:42

sp00m

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answered Feb 4, 2010 at 3:45

TheDon

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1 Comment

vhs Over a year ago

Note to onlookers, tokenize is an unregistered function in XPath 1.0.

soconnor · Accepted Answer · 2010-02-04 03:47:55Z

1

Not sure about getting the multiple attribute values, but change your selector to

//theParentNode[theChildNode]

to get all parents with the child node.

//theParentNode[theChildNode[contains....]]

No need to step up, select only parents that have the child.

answered Feb 4, 2010 at 3:47

soconnor

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1 Comment

prodigitalson Over a year ago

Definitely. Id dont know why i thoughr i couldnt that. Thanks!

Jim Garrison · Accepted Answer · 2010-02-04 03:49:25Z

1

I don't have an XML test environment available at present, but you might pursue this possibility:

//theChildNode[intersect(tokenize(@name, '\s+'),('one','all'))]

answered Feb 4, 2010 at 3:49

Jim Garrison

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1 Comment

prodigitalson Over a year ago

That would be the syntax i would expect and tried initially (only i use | instead of , thinking of an or operator). but got an invalid query (with the , sep as well).

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