Inheritance same methods implementation

Question

I have the following code. (in c#) interface 1:

public interface iBclass
{
   int addition(int a);

   int s(); //and more methods from this ......


}

interface 2:

 public interface iAclass
 {
    int addition(int a);
    //more methods.....
 }

Class that inherits both interfaces:

public class dClass : iAclass , iBclass
{

    int iAclass.addition(int a)
    {
        return 0;
    }

   int iBclass.addition(int a)
    {
        return 1;
    }


   public int s()
   {
       return 3;
   }
}

the problem is i am not able to access the Method iAclass.addition(int a) and iBclass.addition(int a) with the d object.

  dClass d = new dClass();

how can i access those method by 'd' object? and why those interface methods are not allow to define as public?

@markg : my IAclass having extra functions that are not present in the IBclass then? — Avinash patil
– Avinash patil, Commented Feb 24, 2014 at 12:23
@ssilas777: yes.i need return type. void allows the public declaration. but if you add some return type to it then public is not allowed. — Avinash patil
– Avinash patil, Commented Feb 24, 2014 at 12:29

Markus · Accepted Answer · 2014-02-24 12:33:36Z

3

The interfaces are implemented explicitly. So you can only call them by using the interface:

dClass d = new dClass();
iAclass a = (iAclass)d;
a.addition(123);  // Calls implementation for iAclass
iBclass b = (iBclass)d;
b.addition(123);  // Calls implementation for iBclass

See this link for details.

edited Feb 24, 2014 at 12:33

answered Feb 24, 2014 at 12:25

Markus

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