jsonp not working in js code

Question

Here is my code

var api = "http://199.175.xx.xxx:3000?jsoncallback=?";
    $.getJSON( api, {}).done(function( data ) {
        alert('h');
    });

but alert is never happening. I can see from network tab in inspector that request is being sent successfully and also response is the correct one but why alert is not firing inside done callback?

here is the inspector result enter image description here

Does the URL correctly use the jsoncallback parameter to add the callback name to the response? — gen_Eric
– gen_Eric, Commented Feb 24, 2014 at 16:43
P.S. The data parameter in $.getJSON is optional. You don't need to pass {}, you can just do ` $.getJSON(api)`. — gen_Eric
– gen_Eric, Commented Feb 24, 2014 at 16:45
@RocketHazmat How to check its adding parameter correctly or not — FarazShuja
– FarazShuja, Commented Feb 24, 2014 at 16:46
Check the network tab for the response data? What does it look like? JSONP should look like this: callback({"your": "data"}). Also, is it your API or is it a third-party one? Are you sure it should be jsoncallback=?? — gen_Eric
– gen_Eric, Commented Feb 24, 2014 at 16:49
There's your problem right there. It's not using the jsoncallback parameter in the response, like it's supposed to. Did you create this URL, or is it a third-party API? — gen_Eric
– gen_Eric, Commented Feb 24, 2014 at 16:56

Romain Braun · Accepted Answer · 2014-02-24 16:44:54Z

1

Use it this way :

var api = "http://199.175.xx.xxx:3000?jsoncallback=?";
$.getJSON(api, function (data) {
    alert('h');
});

You don't need to use .done()here, as $.getJSON already comes with a callback function.

Source : $.getJSON

answered Feb 24, 2014 at 16:44

Romain Braun

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1 Comment

gen_Eric Over a year ago

He doesn't need .done(), but it should work just fine with it.

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