How to use the conditional operator on $_POST array in PHP?

Question

$myitem = $_POST['item1'] ? myitem : NULL ;

is this possible? I got an error Notice: Undefined index

I use conditioning number of object items by ajax. for example sometime $_POST['item1'] is not passed.

Hein Andre Grønnestad · Accepted Answer · 2014-02-25 08:40:55Z

9

Use isset() for the condition and $_POST['item1'] after the question mark.

$myitem = isset($_POST['item1']) ? $_POST['item1'] : NULL;

answered Feb 25, 2014 at 8:40

Hein Andre Grønnestad

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1 Comment

Hein Andre Grønnestad Over a year ago

Hi! Did my answer help you? I would appreciate if you could accept the answer if it did. Thank you!

Birla · Accepted Answer · 2014-02-25 09:04:54Z

0

I suggest that you use array_key_exists() in place of isset() as the latter one checks for the value also! For example, if the user enter's the number '0' in a field, isset() and empty() will return false while array_key_exists() will return true.

Your code becomes:

$myitem = array_key_exists($_POST['item1']) ? $_POST['item1'] : NULL ;

This is a mistake that most new PHP developers make and it hides in plain sight, giving them nightmares!

answered Feb 25, 2014 at 9:04

Birla

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