How to getText the multiple EditText value in android using For Loop

Question

In My App i have 10 Edittext and 10 TextView

I have created instance for the both EditText and TextView like

String[] messageText=new String[10];
String[] messageEdit=new String[10];
TextView oTextView1 = (TextView) findViewById(R.id.Tab_common1_EditText);
    TextView oTextView2 = (TextView) findViewById(R.id.Tab_common2_EditText);
    TextView oTextView3 = (TextView) findViewById(R.id.Tab_common3_EditText);
    TextView oTextView4 = (TextView) findViewById(R.id.Tab_common4_EditText);
    TextView oTextView5 = (TextView) findViewById(R.id.Tab_common5_EditText);
    TextView oTextView6 = (TextView) findViewById(R.id.Tab_common6_EditText);
    TextView oTextView7 = (TextView) findViewById(R.id.Tab_common7_EditText);
    TextView oTextView8 = (TextView) findViewById(R.id.Tab_common8_EditText);
    TextView oTextView9 = (TextView) findViewById(R.id.Tab_common9_EditText);
    TextView oTextView10 = (TextView) findViewById(R.id.Tab_common10_EditText);

    EditText oEditTextHiden1 = (EditText) findViewById(R.id.Tab_Hidencommon1_EditText);
    EditText oEditTextHiden2 = (EditText) findViewById(R.id.Tab_Hidencommon2_EditText);
    EditText oEditTextHiden3 = (EditText) findViewById(R.id.Tab_Hidencommon3_EditText);
    EditText oEditTextHiden4 = (EditText) findViewById(R.id.Tab_Hidencommon4_EditText);
    EditText oEditTextHiden5 = (EditText) findViewById(R.id.Tab_Hidencommon5_EditText);
    EditText oEditTextHiden6 = (EditText) findViewById(R.id.Tab_Hidencommon6_EditText);
    EditText oEditTextHiden7 = (EditText) findViewById(R.id.Tab_Hidencommon7_EditText);
    EditText oEditTextHiden8 = (EditText) findViewById(R.id.Tab_Hidencommon8_EditText);
    EditText oEditTextHiden9 = (EditText) findViewById(R.id.Tab_Hidencommon9_EditText);
    EditText oEditTextHiden10 = (EditText) findViewById(R.id.Tab_Hidencommon10_EditText);

now i need to get all the TextView getText() and EditText getText()

I have try some method but it is not working

 for (int i = 0; i < 10; i++) {

        messageText[i] = (oTextView+i).getText().toString();//it says oTextView cannot be resolved to a variable
        messageEdit[i] = (oEditTextHiden+i).getText().toString();
      }
      Log.i("message", "message :"+Arrays.deepToString(messageText)+" "+Arrays.deepToString(messageEdit));

put all oTextView on one List<TextView> and work with that — Shayan Pourvatan
– Shayan Pourvatan, Commented Feb 25, 2014 at 12:46
You have to create two array-lists one for text-view and other for Edit-text and then work with that. — AndroidCoder
– AndroidCoder, Commented Feb 25, 2014 at 12:48

Florian Pellegrin · Accepted Answer · 2018-03-25 16:58:38Z

7

Store the ids of the EditText and loop over them, since the View ids are integers, you can do that easily like so :

ArrayList<String> values = new ArrayList<String>();
int[] ids = new int[]{R.id.editText1,R.id.editText2,R.id.editText3};//and so on

for(int id : ids){
    EditText t = (EditText) findViewById(id);
    values.add(t.getText().toString());
}

Or if you only want the text and don't want to do anything else with the EditText view itself, you could make it in one line this:

for(int id : ids) values.add(((EditText)findViewById(id)).getText().toString());

edited Mar 25, 2018 at 16:58

Florian Pellegrin

593 silver badges9 bronze badges

answered Feb 25, 2014 at 12:49

Juan Cortés

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4 Comments

M D Over a year ago

That's what i am talk in about! +1 up

Ayoub Over a year ago

You can also use something like:

EditText text = (EditText) getActivity().findViewById(getResources().getIdentifier("generalname" + number, "id", context.getPackageName()));

Juan Cortés Over a year ago

@Ayoub according to the docs: Note: use of this function is discouraged. It is much more efficient to retrieve resources by identifier than by name.

Chris Over a year ago

Your missing a bracket. Should be: values.add(t.getText().toString());

Chirag Ghori · Accepted Answer · 2014-02-25 12:51:38Z

3

Add all TextView and EdiText in Array Like this

TextView[] oTextView = { oTextView1, oTextView2, oTextView3,
            oTextView4, oTextView5, oTextView6, oTextView7, oTextView8,
            oTextView9, oTextView10 };

EditText[] oEditTextHiden = { oEditTextHiden1, oEditTextHiden2,
            oEditTextHiden3, oEditTextHiden4, oEditTextHiden5,
            oEditTextHiden6, oEditTextHiden7, oEditTextHiden8,
            oEditTextHiden9, oEditTextHiden10 };

Then getText() Should look like this

    for (int i = 0; i < 10; i++) {

        messageText[i] = oTextView[i].getText().toString();
        messageEdit[i] = oEditTextHiden[i].getText().toString();
    }

answered Feb 25, 2014 at 12:51

Chirag Ghori

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Comments

meir shapiro · Accepted Answer · 2014-02-25 12:54:33Z

String[] messageText=new String[10];
String[] messageEdit=new String[10];
TextView[] textViews = new TextView[10];
textViews[0] = (TextView) findViewById(R.id.Tab_common1_EditText);
textViews[1] = (TextView) findViewById(R.id.Tab_common2_EditText);
textViews[2] = (TextView) findViewById(R.id.Tab_common3_EditText);
textViews[3] = (TextView) findViewById(R.id.Tab_common4_EditText);
textViews[4] = (TextView) findViewById(R.id.Tab_common5_EditText);
textViews[5] = (TextView) findViewById(R.id.Tab_common6_EditText);
textViews[6] = (TextView) findViewById(R.id.Tab_common7_EditText);
textViews[7] = (TextView) findViewById(R.id.Tab_common8_EditText);
textViews[8] = (TextView) findViewById(R.id.Tab_common9_EditText);
textViews[9] = (TextView) findViewById(R.id.Tab_common10_EditText);

EditText[] editTexts = new EditText[10];
editTexts[0] = (EditText) findViewById(R.id.Tab_Hidencommon1_EditText);
editTexts[1] = (EditText) findViewById(R.id.Tab_Hidencommon2_EditText);
editTexts[2] = (EditText) findViewById(R.id.Tab_Hidencommon3_EditText);
editTexts[3] = (EditText) findViewById(R.id.Tab_Hidencommon4_EditText);
editTexts[4] = (EditText) findViewById(R.id.Tab_Hidencommon5_EditText);
editTexts[5] = (EditText) findViewById(R.id.Tab_Hidencommon6_EditText);
editTexts[6] = (EditText) findViewById(R.id.Tab_Hidencommon7_EditText);
editTexts[7] = (EditText) findViewById(R.id.Tab_Hidencommon8_EditText);
editTexts[8] = (EditText) findViewById(R.id.Tab_Hidencommon9_EditText);
editTexts[9] = (EditText) findViewById(R.id.Tab_Hidencommon10_EditText);

for (int i = 0; i < 10; i++) {
    messageText[i] = textViews[i].getText().toString();
    messageEdit[i] = editTexts[i].getText().toString();
  }
  Log.i("message", "message :"+Arrays.deepToString(messageText)+" "+Arrays.deepToString(messageEdit));

Eldhose M Babu · Accepted Answer · 2014-02-25 13:02:58Z

The best way to do this is to use the tag associated with the textview.

For example :

In Xml you need to create TextView and editText as following :

<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
xmlns:tools="http://schemas.android.com/tools"
android:id="@+id/llParent"
android:layout_width="match_parent"
android:layout_height="match_parent"
android:orientation="vertical" >

<TextView
    android:layout_width="match_parent"
    android:layout_height="wrap_content"
    android:tag="tv1"
    android:text="TextView1" />

<EditText
    android:layout_width="match_parent"
    android:layout_height="wrap_content"
    android:tag="et1"
    android:text="EditText1" />

<TextView
    android:layout_width="match_parent"
    android:layout_height="wrap_content"
    android:tag="tv2"
    android:text="TextView2" />

<EditText
    android:layout_width="match_parent"
    android:layout_height="wrap_content"
    android:tag="et2"
    android:text="EditText2" />

  ===== Similarly 10 Textviews and EditTexts========

</LinearLayout>

In Code :

String[] messageText = new String[10];
String[] messageEdit = new String[10];

LinearLayout llParent = (LinearLayout) findViewById(R.id.llParent);

    for (int i = 1; i <= 10; i++) {
        messageText[i - 1] = ((TextView) llParent.findViewWithTag("tv" + i))
                .getText().toString();
        messageEdit[i - 1] = ((EditText) llParent.findViewWithTag("et" + i))
                .getText().toString();
    }

Happy Coding.... :-)

AndroidCoder · Accepted Answer · 2014-02-25 12:53:35Z

Try Like This :-

    ArrayList<TextView> arrayListTextViews = new ArrayList<TextView>();
    TextView oTextView1 = (TextView) findViewById(R.id.Tab_common1_EditText);
    TextView oTextView2 = (TextView) findViewById(R.id.Tab_common2_EditText);
    TextView oTextView3 = (TextView) findViewById(R.id.Tab_common3_EditText);
    TextView oTextView4 = (TextView) findViewById(R.id.Tab_common4_EditText);
    TextView oTextView5 = (TextView) findViewById(R.id.Tab_common5_EditText);
    TextView oTextView6 = (TextView) findViewById(R.id.Tab_common6_EditText);
    TextView oTextView7 = (TextView) findViewById(R.id.Tab_common7_EditText);
    TextView oTextView8 = (TextView) findViewById(R.id.Tab_common8_EditText);
    TextView oTextView9 = (TextView) findViewById(R.id.Tab_common9_EditText);
    TextView oTextView10 = (TextView) findViewById(R.id.Tab_common10_EditText);
    arrayListTextViews.add(oTextView1);
    arrayListTextViews.add(oTextView2);
    arrayListTextViews.add(oTextView3);
    arrayListTextViews.add(oTextView4);
    arrayListTextViews.add(oTextView5);
    arrayListTextViews.add(oTextView6);
    arrayListTextViews.add(oTextView7);
    arrayListTextViews.add(oTextView8);
    arrayListTextViews.add(oTextView9);
    arrayListTextViews.add(oTextView10);

and then access textviews from arrayListTextViews in the loop. Also do the same for Your Edittext.

Budius · Accepted Answer · 2014-02-25 12:55:04Z

0

the best way is to use the getIdentifier method in the Resources class

something like that

messageText[i] = (TextView) getActivity().findViewById(getResources().getIdentifier("Tab_common"+i+"_EditText", "id", context.getPackageName()));
messageEdit[i] = (EditText) getActivity().findViewById(getResources().getIdentifier("Tab_Hidencommon"+i+"_EditText", "id", context.getPackageName()));

answered Feb 25, 2014 at 12:55

Budius

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2 Comments

Juan Cortés Over a year ago

getIdentifier Note: use of this function is discouraged. It is much more efficient to retrieve resources by identifier than by name. (From the docs)

Budius Over a year ago

I know it is less efficient, but it's 1 time initialization is not a problem and avoids having to keep track of all those IDs.

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