Has anyone an idea how to get a BufferedInputStream to a byte[] so that I can make a Bitmap of it?
That's my Stream:
BufferedInputStream stream = new BufferedInputStream(socket.getInputStream());
And that's my byte[]:
byte[] bytes;
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2 Answers
uhm... the read() method of the BufferedInputStream will give you the byte[] you need.
For getting a Bitmap, use the BitmapFactory.decodeStream() method and pass in your BufferedInputStream as a parameter. Good to go ! :)
6 Comments
L3n95
So just; byte[] bytes = BitmapFactory.decodeStream(stream);?
An SO User
Bitmap bitmap = BitmapFactory.decodeStream(stream)
Eng.Fouad
+1 For the most right answer. For transparent images (such as: .png), I think you need to specify
BitmapFactory.Options.L3n95
Seems to work but if i want to put the ImageView in to my LinearLayout it says: Only the original thread that created a view hierarchy can touch its views How to fix this?
Eng.Fouad
@LittleChild You should include the main looper:
new Handel(Looper.getMainLooper()).post(runnable); |
BufferedInputStream stream = new BufferedInputStream(s.getInputStream());
ByteArrayOutputStream baos = new ByteArrayOutputStream();
int theByte;
while((theByte = stream.read()) != -1) baos.write(theByte);
Then:
BitmapFactory.Options opt = new BitmapFactory.Options();
opt.inDither = true;
opt.inPreferredConfig = Bitmap.Config.ARGB_8888;
byte[] imageByteArray = bytes;
Bitmap bitmap = BitmapFactory.decodeByteArray(imageByteArray, 0, imageByteArray.length, opt);
imageView.setImageBitmap(bitmap);
4 Comments
An SO User
BitmapFactory.decodeStream() because so that I can make a Bitmap of it :pAn SO User
Still very complex :D Just pass in the stream to
decodeStream() and let Android do the magic ;) It is overloaded. :)Eng.Fouad
@LittleChild Yeah agreed! Too lazy to update it twice :P
L3n95
I tried this now but then it says NullPointerException for outputstream write at: while((theByte = is.read()) != -1) baos.write(bytes); i think "is" should mean stream right?
