why does array.shift skip a value?

Question

I have this function

$(this).each(function(index) {

            arr[index] = ($(this).attr('id'));
            console.log(arr[index]);            

            fullId[index] = "#"+arr.shift();
            console.log(fullId[index]);     
});

The results I'm expecting are

A
#A
B
#B
C
#C
D
#D

The actual results are

A
#A
B
Undefined
C
#B
D
Undefined

Why is this?

Anon. · Accepted Answer · 2010-02-05 01:11:57Z

4

You realize that shifting arr changes the indexes of all items in the array, right?

And yet won't affect $(this) at all?

answered Feb 5, 2010 at 1:11

Anon.

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2 Comments

Catfish Over a year ago

I don't understand your answer/question?

Anon. Over a year ago

Try printing the entirety of arr after each call to shift. It'll make the problem clear.

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