RegEx - find and replace string

Question

i am trying to search my server and find the following in any files.

my regex grep -H -r '/\<\?php\spreg_replace\(\"\/\.\*\/e\"\,\.*?\)\;\?\>/gi' /var/www/html/optinsmart/

i'm looking for this <?php preg_replace("/.*/e"anything in here);?> and i want to replace it with nothing or just simply remove it.

it isn't returning any matches at the command line

but when i do grep '<?php preg_replace("/.*/e"' /var/www/optinsmart/ it returns all of them

is there something wrong in my regex?

EDIT

i am trying to find <?php preg_replace("/.*/e"???);?> where ??? could be anything.

I'm looking for this. Please be specific what you want to achieve instead of just referring to your regex. — Rahil Wazir
– Rahil Wazir, Commented Feb 26, 2014 at 23:07

anubhava · Accepted Answer · 2014-02-26 23:38:01Z

1

You can use grep -F (fixed string without regex):

grep -FHr '<?php preg_replace("/.*/e"' *

To delete these line use this sed:

sed -i.bak '/<?php preg_replace("\/.*\/e"/d' *

edited Feb 26, 2014 at 23:38

answered Feb 26, 2014 at 23:07

anubhava

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5 Comments

JD Vangsness Over a year ago

but i need to get the whole PHP code. <?php preg_replace("/.*/e"???);?> and the ??? could be anything.. gh32947gh9h 0r a word or numbers or dashes...

anubhava Over a year ago

But even that line is also starting with same text '<?php preg_replace("/.*/e"' so should it not be fine?

JD Vangsness Over a year ago

so with will only go to the end of the line?

JD Vangsness Over a year ago

my server got hacked and that code snippet was added to the bottom of all my index.php files. so i want to search for it and remove it from all the files.. Will what you suggested for for that?

JD Vangsness Over a year ago

i ended up using find ./ -name "index.php" | xargs sed -i '/<?php preg_replace("\/.*\/e"/d'. Thnak you for your help and pointing me in the right direction

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