how post files array with Go?

Question

i have a form with many options to post, and post files with slice,but in Go, Request.ParseForm(),only get the first file, how should i resolve with file slice?

in html

<form enctype="multipart/form-data" method="POST" action="/homeworks" >
  {{if .success}}
    <p>flash success</p>
  {{end}}

  <div id="postform">
    本次作业标题
      <input type="text" name="title" />
      <br>
    <div class="postoption"> 
      添加项目
      <input type="text" name="option[]" />
      音频文件
      <input type="file" name="radio[]" />
      答案
      <input type="text" name="answer[]" />
    </div>
  </div>

  <input type="submit" value="提交" />
</form>

if i do like

    file,header,err:=r.FormFile("file")
    fmt.Println(header)
    if err!=nil{
        panic(err)
    }

it will panic no such file, how can i get files slice. if i change it to radio ,it works,but
can not get file slice.

you can try getting a MultipartReader for the request and then read the parts manually. golang.org/pkg/net/http/#Request.MultipartReader — Not_a_Golfer
– Not_a_Golfer, Commented Feb 27, 2014 at 12:37
@Uriel_SVK is right. The string argument to FormFile is the name of the input field defined in html. — Logiraptor
– Logiraptor, Commented Feb 27, 2014 at 15:16

Sumner Evans · Accepted Answer · 2021-08-28 18:56:12Z

1

that's finally how i deal with it, By reading Go source code of formfile()

fhs := r.MultipartForm.File["radio"]

fhs are the Headers of FileHeader of mutlipart .

by useing Open method, i can get the interface file

for i:=0;i<len(fhs);i++{
    f,err:=fhs[i].Open()
}

then i can do the next steps.

edited Aug 28, 2021 at 18:56

Sumner Evans

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answered Feb 28, 2014 at 11:16

ggaaooppeenngg

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