PHP to Javascript array trouble

Question

so I have this code:

var loc = new Array();
        <?php foreach($loc as $key => $val) { ?>
            loc.push('<?php print_r($val); ?>');
        <?php } ?>

The problem is is that it's only showing one value and not more than one, like it should. This is the php array code:

$loc = array($lat, $long);

Any help is greatly appreciated.

print_r is only for debugging. It's not for anything else. — gen_Eric
– gen_Eric, Commented Feb 27, 2014 at 16:25
Why are you using print_r()? It's only used to display a formatted version of your array and is not to be used for transferring data from client <-> server. Use JSON format instead, as shown in Niet's answer below. — Amal
– Amal, Commented Feb 27, 2014 at 16:25

Niet the Dark Absol · Accepted Answer · 2014-02-27 16:36:51Z

9

Try this:

var loc = <?php echo json_encode($loc); ?>;

You should not use print_r. Let me quote the documentation:

print_r — Prints human-readable information about a variable

Note the part I emphasised. "human-readable". Just because it looks vaguely like something JavaScript might understand, doesn't mean it is ;) json_encode, on the other hand, is specifically designed to output JSON, which is a subset of the syntax JavaScript accepts for variables.

edited Feb 27, 2014 at 16:36

answered Feb 27, 2014 at 16:22

Niet the Dark Absol

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2 Comments

Amal Over a year ago

Ninja'd. +1 for being fast (and correct, at the same time).

Amal Over a year ago

I think it'd be better to have a short explanation of why the given code doesn't work :)

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