cURL Command in linux to return http response code

Question

Please i want to use the cURL command in linux OS to return as a result just the http response code which is "200" if it is okey

am using that command:

curl -I -L domain.com

but this is returning for me a full text like this

HTTP/1.1 **200** OK
Date: Thu, 27 Feb 2014 19:32:45 GMT
Server: Apache/2.2.25 (Unix) mod_ssl/2.2.25 OpenSSL/1.0.0-fips mod_auth_passthrough/2.1 mod_bwlimited/1.4 FrontPage/5.0.2.2635 PHP/5.4.19
X-Powered-By: PHP/5.4.19
Set-Cookie: PHPSESSID=bb8aabf4a5419dbd20d56b285199f865; path=/
Expires: Thu, 19 Nov 1981 08:52:00 GMT
Cache-Control: no-store, no-cache, must-revalidate, post-check=0, pre-check=0
Pragma: no-cache
Vary: Accept-Encoding,User-Agent
Content-Type: text/html

so please i just need the response code and not the whole text

Regards

Sabuj Hassan · Accepted Answer · 2014-02-27 19:40:36Z

10

curl -s -o out.html -w '%{http_code}' http://www.example.com

answered Feb 27, 2014 at 19:40

Sabuj Hassan

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5 Comments

user3178889 Over a year ago

this is returing the whole source of the index

user3178889 Over a year ago

ohhh yes . thanks alot i saw the out.html .. not the result on the terminal. thanks sir

Damien Overeem Over a year ago

@user3178889: If you are satisfied with Sabuj's answer. Please click the check mark in front of his answer to accept it. This way it is clear that your question was successfully answered.

lm5050 Over a year ago

I wanted to pull a website html source as a text file, changed out.html to out.txt and the above command worked. Thanks!

lindhe Over a year ago

This is prohibitively slow if the body is large.

Nigel · Accepted Answer · 2020-01-17 20:42:22Z

1

Running the following will supress the output so you won't have any cleanup.

curl -s -o /dev/null -w '%{http_code}' 127.0.0.1:80

Example above uses localhost and port 80

edited Jan 17, 2020 at 20:42

answered Jan 17, 2020 at 19:53

Nigel

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1 Comment

Nigel Over a year ago

Yes, it provides the http code (i.e. 200, etc.) root@70349a8eaf2c:/# curl -s -o /dev/null -w '%{http_code}' 127.0.0.1:80 200root@70349a8eaf2c:/# root@70349a8eaf2c:/#

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