Powershell function throwing null exception

Question

Okay, so I've read up on calling functions and passing parameters in powershell but maybe I'm not understanding something. I am calling a function and passing a couple parameters and everything works fine. It is variable defined within the function that seems to be null when it isn't.

Function:

function get-session {
$session = New-PSSession -ComputerName $ip -Credential $cred -Auth CredSSP
$subcomps = 'COMP1'
foreach ($Computer in $subcomps)
{
$Computer
Invoke-Command -Session $session -ScriptBlock { Get-WmiObject -ComputerName $Computer -Query "SELECT * FROM Win32_Group" }
}
Remove-PSSession -ComputerName $ip
}

Script:

$ip = '123.45.67.89'
$ComputerName = "HOPCOMP"
$user = '\Admin'
$cred = $ComputerName + $user
$ip
$cred
(get-session -ComputerName $ip -Credential $cred)

When I run this:

Cannot validate argument on parameter 'ComputerName'. The argument is null or empty.
Supply an argument that is not null or empty and then try the command again.
+ CategoryInfo          : InvalidData: (:) [Get-WmiObject], ParameterBindingValidationException
+ FullyQualifiedErrorId : ParameterArgumentValidationError,Microsoft.PowerShell.Commands.GetWmiObjectCommand

Of course, if I change $Computer in in the function Get-WMIObject line to COMP1 everything works great. But, the $Computer write out in the foreach loop writes COMP1 successfully.

What am I missing here?

Liam · Accepted Answer · 2018-07-17 12:40:05Z

3

You need to specify the -ArgumentList parameter with your Invoke-Command. For example:

Invoke-Command -Session $session -ScriptBlock { 
       param($Computer) 
       Get-WmiObject -ComputerName $Computer -Query "SELECT * FROM Win32_Group" 
  } -ArgumentList $Computer

edited Jul 17, 2018 at 12:40

Liam

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answered Feb 27, 2014 at 20:52

Arluin

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Comments

Liam · Accepted Answer · 2018-07-17 12:39:13Z

0

The $IP is global and therefore known with the function. The -ArgumentList is needed or populate your $MyScriptBlock a line before acting on it with Invoke-Command.

edited Jul 17, 2018 at 12:39

Liam

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answered Feb 28, 2014 at 22:04

Kirt Carson

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Comments

Liam · Accepted Answer · 2018-07-17 12:39:21Z

0

The function does not know what $ip is.

You need to change the function to accept a parameter of $ip

edited Jul 17, 2018 at 12:39

Liam

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answered Feb 27, 2014 at 19:46

Jimbo

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1 Comment

snoop Over a year ago

It acts like it does. The session opens when you run the script. Could you explain more?

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