PHP Uploading Files Mysql Fail

Question

Can anybody please point out mistakes I make in this code?

for($i=0; $i<count($fileDirectories); $i++){

            echo 'asdasd';
            echo $fileDirectories[$i];
            $queryFiles = "UPDATE maintable SET Picture$i = '$fileDirectories[$i]' WHERE id = $idNeeded;";
            mysqli_query($link, $queryFiles); 
        }

I just cant find a good duide to that

$queryFiles = "UPDATE maintable SET Picture$i = '" . $fileDirectories[$i] . "' WHERE id = '" . $idNeeded ."'"; — user3111737
– user3111737, Commented Feb 28, 2014 at 22:26
Try codereview.stackexchange.com - question as it stands is off-topic here. — symcbean
– symcbean, Commented Feb 28, 2014 at 23:03

Chetan Paliwal · Accepted Answer · 2014-02-28 22:28:51Z

1

$queryFiles = "UPDATE maintable SET Picture$i = '$fileDirectories[$i]' WHERE id = '$idNeeded'";

answered Feb 28, 2014 at 22:28

Chetan Paliwal

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2 Comments

Ababababa Over a year ago

Thanks guys, but i found also another mysql mistake and both of your answers seems not to work because of that

Ababababa Over a year ago

just found the source of mistake. thanks i had a correct syntax from you. now everything works!

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