string manipulation in java array

Question

this code is designed to initialise an array C and its values, then print them and print the largest string within the array. i have used an enhanced for loop. the debug showed an error that 'longest name' was not initialised so i added =null to it when declaring the string but the output of the program always prints null now rather than the longest string in the array please help!

package week14;

public class LabArray {

    public static void main(String[] args) {
        // TODO Auto-generated method stub
        int [] A = new int[5];
        int [] B = new int[5];
        String [] C = {"luke", "elliot", "glenn", "jonny", "jack"};
        int [] D = new int[5];
        int length = C[1].length();
        String longestname;
        int nextlength;
        for (String name: C){
        System.out.println(name);
            nextlength = name.length();
            System.out.println(name.length());
            if (nextlength > length){
                length = nextlength;
                 longestname = name;
            }
        }
        System.out.println("\nthe longest word in the array = " + longestname);
    }
}

Look here:stackoverflow.com/questions/8632857/… Just use the sort method of Collections or Array! — Robert Moskal
– Robert Moskal, Commented Mar 1, 2014 at 0:25

SteveL · Accepted Answer · 2014-03-01 00:28:48Z

2

for initial value in the length you assign the second element of the array which is already the String with the biggest size(elliot) ,so you never getting inside the if loop and you never assign a value to longestname,

Initialize the value of the longestname as well

int length = C[1].length();
String longestname=C[1];

answered Mar 1, 2014 at 0:28

SteveL

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5 Comments

Don Roby Over a year ago

It would be cleaner to just start the length at zero, but this also works.

thanatorr Over a year ago

should i not initialise the above two variables at the [0] array address?

SteveL Over a year ago

You can use any of the array's element for initial value,but the standard way is to use the first element

SteveL Over a year ago

@DonRoby ,what if the array had only empty Strings? you gotta think all the possibilities

Don Roby Over a year ago

Indeed you're right. You definitely should also start the value at the empty string if you're going to start the length at zero.

Zied R. · Accepted Answer · 2014-03-01 00:29:15Z

0

THis code works perfectly :

    int [] A = new int[5];
    int [] B = new int[5];
    int [] D = new int[5];        
    String [] C = {"luke", "elliot", "glenn", "jonny", "jack"};       
    String longestname=null;
    int maxlength=0;
    for(String max:C)
    {
        if(maxlength<max.length())
        {
            maxlength=max.length();
            longestname=max;
        }
    }
    System.out.println("\nthe longest word in the array = " + longestname);

output :

run:

the longest word in the array = elliot
BUILD SUCCESSFUL (total time: 0 seconds)

answered Mar 1, 2014 at 0:29

Zied R.

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