Url encoding issue with url connection

Question

Please help me to encode the url:

http://dsxsd.com/def/fss/default/files/10 رسم الصباح - 1.mp3

I need to download this file in android app. when i am trying to make url connection it gives me 404. but on browser the url is working. when i pasted browser encoded url its working fine.

But i can't hardcore the things as i have my urls like this coming from server.

I tried to encode using Urlencoder.encode(url,"UTF-8"); but server call gives me wrong url I am getting "java.net.MalformedURLException: Protocol not found: http%3A%2F%........

have this url not separate path params and query params to encode separately.

please help me in it.

fge · Accepted Answer · 2014-03-01 11:21:44Z

1

Use URI templates: URLEncoder.encode() does not work.

Usage of the library above:

final URITemplate template = new URITemplate("http://dsxsd.com/def/" +
    "fss/default/files/{filename}");

final VariableMap vars = VariableMap.newBuilder()
    .addScalarValue("filename", "10 رسم الصباح - 1.mp3")
    .freeze();

System.out.println(template.toString(vars));

Output:

http://dsxsd.com/def/fss/default/files/10%20%D8%B1%D8%B3%D9%85%20%D8%A7%D9%84%D8%B5%D8%A8%D8%A7%D8%AD%20-%201.mp3

answered Mar 1, 2014 at 11:21

fge

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8 Comments

Philio Over a year ago

For this particular example, your library doesn't achieve anything that you cannot achieve with URLEncoder.

Rajiv yadav Over a year ago

agree but, and library looks promising . can't i get a simple project other than Gradle build. its hard for person who don't use Gradle to configure it.

fge Over a year ago

@Rajivyadav why clone the project? Just use the gradle/maven artifact

Rajiv yadav Over a year ago

sorry i am getting . Error generating final archive: Found duplicate file for APK: ASL-2.0.txt Origin 1: /home/user/.gradle/caches/modules-2/files-2.1/com.github.fge/jackson-coreutils/1.5/5108553833b399fed6a1f7f979b89a07b786d3c2/jackson-coreutils-1.5.jar Origin 2: /home/user/.gradle/caches/modules-2/files-2.1/com.github.fge/btf/1.1/597aaacc063dcf8b77c17729706b895c562b162e/btf-1.1.jar

fge Over a year ago

@Rajivyadav that looks like a bug... Could you open a bug in github? In particular, describe your build environment (what is APK for instance?)

|

Philio · Accepted Answer · 2014-03-02 19:27:52Z

1

The problem is that you're encoding the entire URL, you only need to encode the filename, e.g.

String filename = Uri.encode("10 رسم الصباح - 1.mp3");
String url = "http://dsxsd.com/def/fss/default/files/" + filename;

edited Mar 2, 2014 at 19:27

answered Mar 1, 2014 at 11:09

Philio

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5 Comments

Rajiv yadav Over a year ago

I am getting this url from server. I am not configuring it locally . BTW i tried to sub string it and encoding it it is returing dsxsd.com/def/fss/default/files/… which is not a right url.

Philio Over a year ago

In that case, you could split the URL and just encode the last part of that path.

Rajiv yadav Over a year ago

that is not helping me out. spaces creates problem .

fge Over a year ago

@Philio no it won't... "+" is not a valid regex... You probably mean .replace(), and even then the set of characters URLEncoder encodes is not the same set as required by a URI path segment; see the README of the project I linked to for more details...

Philio Over a year ago

True, it would need to be escaped. However, Uri.encode is a better solution anyway as it correctly encodes spaces. Solution updated.

Ayoub GHAFFOUR · Accepted Answer · 2019-06-01 12:07:45Z

If you only have the URL, use this method

private String encodeUrl(String link) throws UnsupportedEncodingException {
    Uri uri = (Uri.parse(link));
    String result = null;
    if (Objects.equals(uri.getScheme(), "content")) {
        try (Cursor cursor = getContentResolver().query(uri, null, null, null, null)) {
            if (cursor != null && cursor.moveToFirst()) {
                result = cursor.getString(cursor.getColumnIndex(OpenableColumns.DISPLAY_NAME));
            }
        }
    }
    if (result == null) {
        result = uri.getPath();
        int cut = Objects.requireNonNull(result).lastIndexOf('/');
        if (cut != -1) {
            result = result.substring(cut + 1);
        }
    }
    return link.replace(result
            ,URLEncoder.encode(result, "UTF-8")
                    .replace("+", "%20"));
}

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