PHP preg_replace add comma

Question

This is my code

$keywords = mysql_escape_string(preg_replace("/[^ \w]+/", '',($_POST['keywords'])));

and this my output

sample products products sample

Here I don't want to replace comma also.

The input is

sample products!@, products#$#, sample

You mean like "/[^ \w,]+/".... is this really rocket science? — Mark Baker
– Mark Baker, Commented Mar 3, 2014 at 12:16

Tom Fenech · Accepted Answer · 2014-03-03 12:25:52Z

2

If you don't want to get rid of ,s, you can add them to your group in the square brackets:

preg_replace("/[^, \w]+/", '',($_POST['keywords']))

edited Mar 3, 2014 at 12:25

answered Mar 3, 2014 at 12:17

Tom Fenech

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krishna · Accepted Answer · 2014-03-03 12:39:13Z

1

try this

$keywords = preg_replace("/[^A-Z, ]/i", '',($_POST['keywords']));
echo $keywords;

Demo

Note: this replaces the content which does not match with the regex. Here it replaces anything except alpabets(case in-sensitive ) and comma , and blank space

edited Mar 3, 2014 at 12:39

answered Mar 3, 2014 at 12:18

krishna

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3 Comments

Anonymous Over a year ago

This would change what is qualified as a match since \w also matches underscores.

krishna Over a year ago

yes correct , based on assumption he need only alphabets and , i have written this regex

Anonymous Over a year ago

Still, he/she may need them to be included for one reason or another so you should at least warn the op that the matches may be different.

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