From the given two lists:
fruits = ['apple', 'banana', 'kiwi', 'mango', 'avocardo']
quantities = [5, 8, 7, 15, 22]
How to get the result below?
fruits_having_less_than_10quantities = ['apple', 'banana', 'kiwi']
I am looking for implementing it using dictionary.
fruits = ['apple', 'banana', 'kiwi', 'mango', 'avocardo']
quantities = [5, 8, 7, 15, 22]
fhlt = [fruit for fruit,num in zip(fruits,quantities) if num < 10]
# => ['apple', 'banana', 'kiwi']
Edit or as a dictionary:
fruitnum = {fruit:num for fruit,num in zip(fruits, quantities) if num < 10}
# => {'apple': 5, 'banana': 8, 'kiwi': 7}
Edit2: if you are concerned about extra temporary lists, in Python 2, you can
from itertools import izip
fhlt = [fruit for fruit,num in izip(fruits,quantities) if num < 10]
instead; in Python 3 this is not necessary, as zip is already a generator.
I really think you should use a dictionary {fruit: quantity} but here you are
>>> fruits = ['apple', 'banana', 'kiwi', 'mango', 'avocardo']
>>> quantities = [5, 8, 7, 15, 22]
>>> fruits_having_less_than_10quantities = [ elem[0] for elem in zip(fruits, quantities) if elem[1] < 10 ]
>>> fruits_having_less_than_10quantities
['apple', 'banana', 'kiwi']
Another option:
[fruits[i] for i in xrange(0, len(fruits)) if quantities[i] < 10]
The above has the advantage that it doesn't create any extra temporary lists. As others have pointed out, this is not a dictionary-type problem, but still…
I think we can trying using bisect:
from bisect import bisect
def disect(fr, qr, n, side=None):
ind = bisect(zip(*sorted(zip(fr, qr), key=lambda tup: tup[1]))[1], n)
if side == 'left':
return fr[:ind]
elif side == 'right':
return fr[ind:]
raise Exception("which side you want")
fruits = ['apple', 'banana', 'kiwi', 'mango', 'avocardo']
quantities = [5, 8, 7, 15, 22]
print disect(fruits, quantities, 10, 'left')
print disect(fruits, quantities, 10, 'right')
