I am writing a regular expression to replace a char from string.The char to be removed is decided at run time.So,is there any way to put variable in regex.
e.g- var reg:RegExp=/[some vaiable]/g;
I don't want to use the new operator to make regular expression.
Thanks in advance.
Unfortunately, your constraints make this impossible.
As per Adobe's help on regular expressions:
Forward slashes delineate a regular expression literal in the same way as quotation marks delineate a string literal.
and
When using the new constructor, you use two strings to define the regular expression. The first string defines the pattern
If you want the regex to be defined at runtime, i.e. not be literal, you have to use the second format. It's not at all hard!
var reg:RegExp = new RegExp(some_variable, "g");
It's exactly equivalent to what you want except for one major difference: this way works, while your way doesn't.
// syntax is only for literal expressions. Since you're inserting a variable into it, it's not literal, and you're stuck with the new syntax.var str:String = "abcdesome_variablefghijklmnop" doesn't parse some_variable. You can do var str:String = "abcde" + some_variable + "efghijklmnop" - but that's constructing a string variable by concatenating 2 literals and a variable. Similarly in this case, you can't create a literal RegExp with a variable in it, but you can create one using a string variable.