PHP - Return an array from loop's value in a function

Question

For example, I have a function like this:

function loopValues()
{
    $a = array('a','b','c');
    foreach($a as $b)
    {
        $c = $b.'e';
        echo $c;
    }
}

How could I return its value aebece in an array like ('ae','be','ce')?

John Conde · Accepted Answer · 2014-03-07 14:23:51Z

3

$a = array('a','b','c');
$b = array_map(function($ele) {
    return $ele .= 'e';
}, $a);

See it in action

answered Mar 7, 2014 at 14:23

John Conde

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Comments

Nouphal.M · Accepted Answer · 2014-03-07 14:22:34Z

2

Try

function loopValues()
{
    $a = array('a','b','c');
    $result = array();
    foreach($a as $b){
        $result[] = $b.'e';
    }
    return $result;
}

$r = loopValues();
print_r($r);

See demo here

answered Mar 7, 2014 at 14:22

Nouphal.M

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Comments

RiggsFolly · Accepted Answer · 2014-03-07 14:21:55Z

1

Simple, try this:

function loopValues()
{
    $a = array('a','b','c');
    $r = array();
    foreach($a as $b)
    {
        $c = $b.'e';
        $r[] = $c;
    }
    return $r;
}

answered Mar 7, 2014 at 14:21

RiggsFolly

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Comments

Andrew Barber · Accepted Answer · 2014-03-07 14:59:16Z

0

function loopValues(){
   $a = array('a','b','c');
   for($i=0;$i<count($a);$i++){
      $a[$i] .= 'e';
   }
   return $a;
}

edited Mar 7, 2014 at 14:59

Andrew Barber

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answered Mar 7, 2014 at 14:37

user3393016

1

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