Print values in php array

Question

I have a problem with this php code.

$q=$cn->exec('call get_count(1,@no_of_users)');
$res=$cn->query('select @no_of_users')->fetchAll();
echo "users".$res['@no_of_users']; 
print_r($res);

I get this output.

usersArray ( [0] => Array ( [@no_of_users] => 3 [0] => 3 ) )

Can anyone tell me how to echo value 3 only. That means I need to show the value of '@no_of_users'.

$res[0]['@no_of_users']

Jonathan Kuhn
– Jonathan Kuhn

2014-03-07 21:11:08 +00:00
Commented Mar 7, 2014 at 21:11 — Jonathan Kuhn
– Jonathan Kuhn, Commented Mar 7, 2014 at 21:11

Abhik Chakraborty · Accepted Answer · 2014-03-07 21:11:18Z

2

You can do as

echo $res[0]["@no_of_users"];

answered Mar 7, 2014 at 21:11

Abhik Chakraborty

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Irek Kubicki · Accepted Answer · 2014-03-07 21:12:43Z

0

If $cn holds PDO instance use fetchColumn() instead of fetchAll()

answered Mar 7, 2014 at 21:12

Irek Kubicki

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