How to create button with a link, with variable

Question

I am trying to create button thats redirect me to another page. I am trying to put variable in the link but the button isnt working.

this is my script:

$idSelect[i]="SELECT * FROM times WHERE id=" . $mid[i] . "";
$idResult[i]=mysqli_query($con,$idSelect[i]); 

while($row = mysqli_fetch_array($idResult[i])) {
$uid[i]=$row['userid'];
}

$inc = "in.php?id=". $uid[i] ."";

echo "<input type='submit' value='back' class='button' onclick='window.location.href=". $inc ."'>";

notes:

ID prints Int from databse.
echo $inc is working, I checked it.

I tried few tutorials, and I read answers from for the same question but they didnt help

EDIT: I think my mistake is something with the onclick place, but I dont know what is the problem..

if you think the error is Javascript error, then check in your browser console ... you will see what the error is — Tun Zarni Kyaw
– Tun Zarni Kyaw, Commented Mar 8, 2014 at 8:21

anurupr · Accepted Answer · 2014-03-08 08:23:43Z

1

You didn't enclose the link.

So your html output would look like this

<input type="submit" value="back" class="button" onclick="window.location.href=in.php?id=1">

so javascript will look for a variable called in

This should work

echo "<input type='submit' value='back' class='button' onclick='window.location.href=\"". $inc ."\"'>";

answered Mar 8, 2014 at 8:23

anurupr

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Suman Bogati · Accepted Answer · 2014-03-08 08:14:48Z

0

You can do something like this.

$inc = "http://in.yahoo.com/?p=us";
echo "<input type='submit' value='back' class='button' onclick='redirect()'>";

echo ("<script>
function redirect(){
    window.location.href = '$inc';
}
</script>");

answered Mar 8, 2014 at 8:14

Suman Bogati

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Comments

Channaveer Hakari · Accepted Answer · 2014-03-08 11:30:46Z

0

Hey use onclick='window.location.replace' as below-

echo "<input type='button' value='back' class='button' onclick='window.location.replace="'. $inc .'"'>";

answered Mar 8, 2014 at 11:30

Channaveer Hakari

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