Lets assume I have a string:
asdf/dfa/fds?adsf
I want to be able to get the string: asdf?adsf
So essentially I want to parse out everything from the first '/' to the '?'.
I tried experimenting with it (see example below) but I couldn't get it to work:
s = s.replaceAll("\\/([?]*)", "");
You should change it to this:
s = s.replaceAll("/.*(?=\\?)", "");
(?=\\?) is a look-ahead that means "the next character is a literal ?". (FYI, unescaped, ? has special meaning in a regex.)
However, you did not mention what should happen if there are multiple ?. The regex above will match until the last one.
If you want to match until the first,
s = s.replaceAll("/.*?(?=\\?)", "");
The extra ? causes the repeated match to be "reluctant".
/ so no \\ is needed before /. Also it seems that OP input is link so there cant be any second ? in it, but I like the way you include this possibility in your answer :)
This should do the trick
replaceAll("/[^?]*", "")
/[^?]* will match first / and all non-? characters after it.
try this
String s = "asdf/dfa/fds?adsf".replaceAll("/.*(?=\\?)", "");
