Forloop and Javascript submit in PHP

Question

I have a code like this.

As per my previous question, I DONT WANT to send any values in the URL and going with the hidden field.

In the below code, when I submit the form, i was able to get the post values in the next page for the first row value only (first while loop record).

Why? When I inspect it with firebug I was able to see the hidden values for all the records.

In other words, only the first record is getting posted to the next page and not the consecutive records.

If the below code looks crazy, could someone help me in such a way that I don't want to pass the values in URL or anywhere in the browser/webform

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
    <meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1" />
    <title>Books</title>
    <script type="text/javascript">
            function test() {
                document.forms.testform.submit();
            }
    </script>
</head>

<body>

    <?php
         mysql_connect("localhost","root","password");
         mysql_select_db("books");
         $result = mysql_query("SELECT B_Code,Author_Name FROM books");  
         while($row = mysql_fetch_array( $result )) {  
    ?>

    <form action ="post.php" id="testform" method="post">
        <input type="hidden" name="name" value="<?php echo $row['B_Code']; ?>" />
        <input type="hidden" name="id" value="<?php echo $row['Author_Name']; ?>" />
    </form>

    <a href="#" onclick="test()"><?php echo $row['Author_Name']; ?></a>

    <?php } ?>

</body>
</html>

Thanks, Kimz

Using the same names for all the hidden fields?? And you are having multiple forms. Hence only those record of the form you click would get submitted. — rakhi4110
– rakhi4110, Commented Mar 10, 2014 at 4:10
Yes Yes ;) You are right. Same name and id for all the records in a hidden field — user3350885
– user3350885, Commented Mar 10, 2014 at 4:11
FYI - even if i change the form name for both the values, I'm not able to get the values in the next page. — user3350885
– user3350885, Commented Mar 10, 2014 at 4:13

rynhe · Accepted Answer · 2014-03-10 04:21:00Z

Try this solution...

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
        <html xmlns="http://www.w3.org/1999/xhtml">
        <head>
        <meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1" />
        <title>Books</title>
        <script type="text/javascript">
        function test(name,id)
        {
        document.getElementById("name").value = name;
        document.getElementById("id").value = id;
        document.forms.testform.submit();
        }
        </script>
        </head>
        <body>
        <form action ="post.php" id="testform" method="post">
        <?php
        mysql_connect("localhost","root","password");
        mysql_select_db("books");
        $result = mysql_query("SELECT B_Code,Author_Name FROM books");  
        while($row = mysql_fetch_array( $result )) {  
        ?>
        <a href="#" onclick="test('<?php echo $row['B_Code']; ?','<?php echo $row['Author_Name']; ?>')"><?php echo $row['Author_Name']; ?></a>
        <?php } ?>
        <input type="hidden" name="name" value="" id="name"/>
        <input type="hidden" name="id" value="" id="id"/>
        </form>
        </body>
        </html>

Laukik Patel · Accepted Answer · 2014-03-10 04:24:13Z

0

why you need to submit form using javascript, you can submit form without javascript. use Please remove a tag and use button type submit.

edited Mar 10, 2014 at 4:24

answered Mar 10, 2014 at 4:18

Laukik Patel

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