PHP not assigning variable

Question

I am sending information to a php file through a AJAX post mat hod and the PHP can echo the data but will not assign it to a variable and I can not seem to understand why. The first echo works but the second echo only seems to get the hours. The AJAX in not encoded.

I just learned PHP a few weeks ago so I expect this problem to be very simple to fix.

Thank you

<?php
    echo ($_POST['userName']);
    $usernam = ($_POST['userName']);
    $eventid = ($_POST['eventid']);
    $hours = ($_POST["hours"]);
    echo $eventid+$usernam+$hours+"<br><br><br>";
?>

Quotes? Strings inside double-quotes " are parsed, strings inside single quotes ' are not. So echo "$a"; gives the value of a, the same as echo $a; but echo '$a'; gives the literal string $a not its value. Parentheses ( ) like in math are used to force precedence (isolate a calculation/condition), e.g. ($a - $b) * $c may not equal $a - $b * $c and if (($a || $b) && $c) may not equal if ($a || $b && $c) — Popnoodles
– Popnoodles, Commented Mar 11, 2014 at 12:30
Yes you need them. You're producing "Use of undefined constant" notices without them. Pick one type (single or double) and stick with it, otherwise you'll end up searching for both variations, should you need to find something. — Popnoodles
– Popnoodles, Commented Mar 12, 2014 at 16:14

13ruce1337 · Accepted Answer · 2014-03-11 01:39:32Z

3

concatenate with .

echo $eventid.$usernam.$hours."<br><br><br>";

I've done this countless times when going back and forth with php and javascript

answered Mar 11, 2014 at 1:39

13ruce1337

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