PHP Pass array between two functions

Question

I currently have 2 functions; i need to read one array that's inside one of the functions from the inside of the other function:

function a(){

 foreach ($options as $option){ // $options is a variable from function b()
  // here goes a really long loop
 }

}

function b(){

 $options[] = array(
   'key1' => 1,
   'key2' => 2,
   'key3' => 3,
  );

 function a(); // run function here?
}

My php file is gonna have multiple copies of what we call "function b()". And inside each function b(), i wanna run function a(), but use the array content that's inside the function b().

function a() contains a loop that's always the same but really long, i just want to keep my code as short as possible instead of copying function a() inside each function b().

This is probably really easy but i've been struggling with this issue for a long time now!

John Conde · Accepted Answer · 2014-03-12 00:28:05Z

3

Just return the array from b() and then pass it as a parameter to a()

function a($options){
    foreach ($options as $option){ 
      // here goes a really long loop
    }
}

function b(){
   $options = array(
       'key1' => 1,
       'key2' => 2,
       'key3' => 3,
   );
   a($options);
}

edited Mar 12, 2014 at 0:28

answered Mar 12, 2014 at 0:17

John Conde

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2 Comments

user2994294 Over a year ago

forgot to mention that i must run function a() inside function b(). function b() is in my scenario a tab on a webpage. Got another solution?

John Conde Over a year ago

Updated my answer accordingly

h2ooooooo · Accepted Answer · 2014-03-12 00:16:44Z

1

Could you not simply pass it as a function argument?

function a($options){
    foreach ($options as $option){ // $options is a variable from function b()
        // here goes a really long loop
    }
}

function b(){
    a(array(
        'key1' => 1,
        'key2' => 2,
        'key3' => 3,
    ));
}

answered Mar 12, 2014 at 0:16

h2ooooooo

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