Using variable as keyword passed to **kwargs in Python

Question

I have a function that updates a record via an API. The API accepts a variety of optional keyword parameters:

def update_by_email(self, email=None, **kwargs):
    result = post(path='/do/update/email/{email}'.format(email=email), params=kwargs)

I have another function that uses the first function to update an individual field in the record:

def update_field(email=None, field=None, field_value=None):
    """Encoded parameter should be formatted as <field>=<field_value>"""
    request = update_by_email(email=email, field=field_value)

This doesn't work. When I call:

update_field(email='[email protected]', field='name', field_value='joe')

the url is encoded as:

https://www.example.com/api/do/update/email/[email protected]?field=Joe

How can I get it to encode as:

https://www.example.com/api/do/update/email/[email protected]?name=Joe

Thank you in advance.

jonrsharpe · Accepted Answer · 2014-03-13 16:17:55Z

17

Rather than passing the parameter named as field, you can use dictionary unpacking to use the value of field as the name of the parameter:

request = update_by_email(email, **{field: field_value})

Using a mock of update_by_email:

def update_by_email(email=None, **kwargs):
    print(kwargs)

When I call

update_field("[email protected]", "name", "joe")

I see that kwargs inside update_by_email is

{'name': 'joe'}

edited Mar 13, 2014 at 16:17

answered Mar 13, 2014 at 16:12

jonrsharpe

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