Trying to pass an array to a function in c

Each of your functions declares a new array, rather than using the array passed to it as an argument.

void displayNums(int print[])
{
    int i;
    int output;
    int numbers[NUMS];
    output = myNumbers(numbers);
    printf("Your numbers are %d \n", output);
}

Note that nowhere is the print argument used, and you're using int numbers[NUMS] instead. Remove that declaration and use print. (Also please consider naming your argument something other than print; this name is confusing and does not accurately describe what the variable stores.)

you are not using arrays properly to communicate the numbers, see the function

int myNumbers(int userPick[]) //implememt function 
{
    int i;
    int numbers;
    int input[NUMS];
    printf ("Please enter your lucky numbers\n");

    for (i=0;i<NUMS;i++)//loop through array to take input
    {
        scanf("%d",&input[i]);                
    }//end for loop
    numbers = *(input+i);

    return (numbers);        
}//end function myNumbers

it reads the number to a local array and returns *(input+i) which will be a random number since your read array is from input+0 to input+i-1. you should pass array or pointer to global array.

Even in case of display() function you are passing one array and using some other array inside display() function.
you should use a common array to communicate values. you can create a array in global scope and use it in all functions or create a array in main() and pass pointer to it to other functions and use the same array in other functions. learn how to pass arrays between functions and use arrays

Your functions looks erroneous:

1. int myNumbers(int userPick[]) // 1. userPick is not used anywhere
   {
   
   int i;
   int numbers;               // 2. initialize this variable to 1 first 
   int input[NUMS];
   printf ("Please enter your lucky numbers\n");
   
   for (i=0;i<NUMS;i++)
   {
       scanf("%d",&input[i]);                
   }//end for loop
   numbers = *(input+i);     // 3. is this suppose to be inside the loop ?
   
   return (numbers);
   }//end function myNumbers
   

And in

void displayNums(int print[])//implement function
{
    int i;
    int output;
    int numbers[NUMS];
    output = myNumbers(numbers);
    printf("Your numbers are %d \n",output);
}//end function displayNums

You don't use print but create a new array numbers

Most of your code is erroneous. It won't compile. Here's some sample code. Work with it to implement the rest

#include <stdio.h>
#define NUMS 6

void displayNums(int nums[])
{
    int i;
    printf("Your numbers are:\n");
    for(i = 0; i < NUMS; i++)
        printf("%d ", nums[i]);
    printf("\n");
}

void myNumbers(int nums[])
{
    printf("Please Enter your lucky numbers\n");
    int i;
    for(i = 0; i < NUMS; i++)
        scanf("%d", &nums[i]);
}

int main()
{
    int numbers[6];
    myNumbers(numbers);
    displaynums(numbers);

    //do the rest of the stuff here

    return 0;
}

Going through a C tutorial might be helpful? Check out http://c.learncodethehardway.org/book/ for a nice intro to the language.