How to transform xml file to another file using xslt ? The code should be in java

Question

I am getting fatal error: The prefix "xsl" for element "xsl:stylesheet" is not bound.

ERROR: 'The prefix "xsl" for element "xsl:stylesheet" is not bound.' FATAL ERROR: 'Could not compile stylesheet' javax.xml.transform.TransformerConfigurationException: Could not compile stylesheet at com.sun.org.apache.xalan.internal.xsltc.trax.TransformerFactoryImpl.newTemplates(Unknown Source) at com.sun.org.apache.xalan.internal.xsltc.trax.TransformerFactoryImpl.newTransformer(Unknown Source) at com.quicklyjava.JavaXSLT.main(JavaXSLT.java:20)

<xsl:stylesheet version="1.0"> 
 <xsl:template match="/">
  <html>
   <body>
    <h1>Movies</h1>
    <table border="3">
     <tr bgcolor="grey">
    <th>Genre</th>
    <th>Title</th>
    <th>Director</th>
    <th>Price</th>
     </tr>
   <xsl:for-each select="movies/movie">
     <tr>
    <td>
        <xsl:value-of select="@genre"/>
    </td>
    <td>
        <xsl:value-of select="title"/>
    </td>
    <td>
        <xsl:value-of select="director"/>
    </td>
    <td>
        <xsl:value-of select="price"/>
    </td>
      </tr>
   </xsl:for-each>
   </table>
   </body>
  </html>
</xsl:template>
</xsl:stylesheet>

Yurii · Accepted Answer · 2014-03-20 07:49:29Z

2

I suppose you're missing the xsl namespace declaration:

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">

answered Mar 20, 2014 at 7:49

Yurii

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2 Comments

Mathias Müller Over a year ago

@user3073182 To be more clear, please accept this answer if it solved your problem.

Michael Kay Over a year ago

Also, I know we all have to start somewhere, but I'm puzzled as to why it was necessary to ask this question. If the message isn't self-explanatory, then you need to do some reading before do any more coding; you're not going to understand error messages unless you understand the concepts of the language, and the only way to understand the concepts is to read before your write.

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